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Updated on: 21 Jun 2019, 10:37
Originally posted by EgmatQuantExpert on 04 Apr 2018, 06:45.
Last edited by bb on 21 Jun 2019, 10:37, edited 7 times in total.
Last edited by bb on 21 Jun 2019, 10:37, edited 7 times in total.
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E
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Learn when to “Add” and “Multiply” in Permutation & Combination questions- Exercise Question #3
A committee needs to be formed of 3 women and 2 men from a group of 6 women and 5 men. Among the chosen members, one needs to be selected for the post of the President, and one for the post of Secretary. In how many ways can the President and Secretary be chosen from this committee formed?
Options:
A) 200
B) 400
C) 600
D) 800
E) 4000
Learn to use the Keyword Approach in Solving PnC question from the following article:
Learn when to “Add” and “Multiply” in Permutation & Combination questions
A committee needs to be formed of 3 women and 2 men from a group of 6 women and 5 men. Among the chosen members, one needs to be selected for the post of the President, and one for the post of Secretary. In how many ways can the President and Secretary be chosen from this committee formed?
Options:
A) 200
B) 400
C) 600
D) 800
E) 4000
Learn to use the Keyword Approach in Solving PnC question from the following article:
Learn when to “Add” and “Multiply” in Permutation & Combination questions
04 Apr 2018, 07:21
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EgmatQuantExpert
Question:
A committee needs to be formed of 3 women and 2 men from a group of 6 women and 5 men. Among the chosen members, one needs to be selected for the post of the President, and one for the post of Secretary. In how many ways can the President and Secretary be chosen from this committee formed?
Options:
A) 200
B) 400
C) 600
D) 800
E) 4000
From grp of 6 women and 5 men , 3 women and 2 men can be selected in 6C3*5C2.
among total selected 5, 5C1 ways for president and 4C1 ways for Secretary .
so total ways=6C3*5C2*5C1*4C1 =4000
option E
Total ways=6C3*5C2*5C1*4C1 =4000
option E
General Discussion
04 Apr 2018, 07:34
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We need to form the group first
From group of 6 women and 5 men , 3 women and 2 men can be selected in 6C3*5C2.= 20*10=200
among total selected 5, we need to select 2 persons- 1 for president , 1 for Secretary = selection and ordering of 2 persons= 5C2*2! =20
so total ways=200*20 =4000
Answer E
From group of 6 women and 5 men , 3 women and 2 men can be selected in 6C3*5C2.= 20*10=200
among total selected 5, we need to select 2 persons- 1 for president , 1 for Secretary = selection and ordering of 2 persons= 5C2*2! =20
so total ways=200*20 =4000
Answer E
