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23 Aug 2007, 19:48
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A committee of 3 has to be formed randomly from a group of 6 people. Tom and Mary are in this group of 6. What is the probability that Tom will be selected into the committee but Mary will not?
1/10
1/5
3/10
2/5
1/2
This question is a lot easier than I made it out to be. What do you see in the question that tips you off to the easiest method to solve? I keep confusing something in these types of probability questions. Thanks for the help!
1/10
1/5
3/10
2/5
1/2
This question is a lot easier than I made it out to be. What do you see in the question that tips you off to the easiest method to solve? I keep confusing something in these types of probability questions. Thanks for the help!
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23 Aug 2007, 20:47
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Brrr - I got 1/10
1st person - Tom: 1/6
2nd person - not Mary 4/5
3rd person - not Mary - 3/4
P = 1/6 * 4/5 * 3/4 = 1/10
P.S> If Tom is 2nd or 3rd - there are no such answers for this probability in the answer choices
1st person - Tom: 1/6
2nd person - not Mary 4/5
3rd person - not Mary - 3/4
P = 1/6 * 4/5 * 3/4 = 1/10
P.S> If Tom is 2nd or 3rd - there are no such answers for this probability in the answer choices
23 Aug 2007, 22:39
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total committees : 6c3 = 20
committees with only tom = 6
ans : 6/20 = 3/10
committees with only tom = 6
ans : 6/20 = 3/10
