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12 Sep 2025, 00:37
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Difficulty:
35%
(medium)
Question Stats:
65% (01:23) correct
35%
(01:32)
wrong
based on 85
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A computer dealership has a number of computers to be sold by its sales persons. How many computers are up for the sale?
(1) If each of the sales persons sells 5 of the computers, 18 computers will remain in stock.
(2) If each of the sales persons sells 4 of the computers, 28 computers will remain in stock.
(1) If each of the sales persons sells 5 of the computers, 18 computers will remain in stock.
(2) If each of the sales persons sells 4 of the computers, 28 computers will remain in stock.
12 Sep 2025, 00:57
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A computer dealership has a number of computers to be sold by its sales persons. How many computers are up for the sale?
(1) If each of the sales persons sells 5 of the computers, 18 computers will remain in stock.
Insufficient
N = 5*X + 18
Where N is number of computers and X is number of sales person
(2) If each of the sales persons sells 4 of the computers, 28 computers will remain in stock.
Insufficient
N = 4*Y + 28
Where N is number of computers and Y is number of sales person
Combining (1) and (2),
5*X + 18 = 4*Y + 28
5*X = 4*Y + 10
We will get different pairs of (X,Y) so together is not sufficient
(E) is the answer
(1) If each of the sales persons sells 5 of the computers, 18 computers will remain in stock.
Insufficient
N = 5*X + 18
Where N is number of computers and X is number of sales person
(2) If each of the sales persons sells 4 of the computers, 28 computers will remain in stock.
Insufficient
N = 4*Y + 28
Where N is number of computers and Y is number of sales person
Combining (1) and (2),
5*X + 18 = 4*Y + 28
5*X = 4*Y + 10
We will get different pairs of (X,Y) so together is not sufficient
(E) is the answer
12 Sep 2025, 01:34
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Logically the no. of sales persons in given time should be same. Any comments on that?
agrasan
