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joemama142000
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ashkapoo
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vipin7um
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ashkapoo
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Got that one wrong... Vipin is right.

If A is cross-sectional area, and V is volume:

AH=1/2*V (had this eqn the other way round in my calcs :x )
HA-hA=500
Eliminate A for the answer.

Thanks Vipin...
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M8
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vipin7um
1000H/(H-h)

- Vipin


Vipin please elaborate it.
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Volume of the pool = lb(2H) (assume l is length and b is breadth)

After draining:

500 = lb(H-h)

or lb = 500/(H-h)


substituting lb in the first eq

Volume = 1000H/(H-h)
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M8
vipin7um
1000H/(H-h)

- Vipin

Vipin please elaborate it.


Hi M8,
Let us say the area is A.

=> V = A * 2H - (1)

Also 500 ltr of water reduces the hight from H to h

=> 500 = A * (H-h) - (2)

Solving (1) and (2) for A gives the Volume.

HTH...



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