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24 May 2026, 19:00
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A
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Difficulty:
45%
(medium)
Question Stats:
71% (01:51) correct
29%
(01:49)
wrong
based on 105
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A cyclist followed a two-leg route from a riverside park to a lookout point. If the second leg of the route was twice as long as the first leg, what was the cyclist’s average (arithmetic mean) speed for the entire route?
(1) The cyclist’s average (arithmetic mean) speed was 12 kilometers per hour on the first leg and 24 kilometers per hour on the second leg.
(2) The cyclist spent the same amount of time on the first leg as on the second leg.
(A) Statement 1 alone is sufficient, but statement 2 alone is not.
(B) Statement 2 alone is sufficient, but statement 1 alone is not.
(C) Both statements together are sufficient, but neither alone is sufficient.
(D) Each statement alone is sufficient.
(E) Neither statement is sufficient, even when combined.
(1) The cyclist’s average (arithmetic mean) speed was 12 kilometers per hour on the first leg and 24 kilometers per hour on the second leg.
(2) The cyclist spent the same amount of time on the first leg as on the second leg.
(A) Statement 1 alone is sufficient, but statement 2 alone is not.
(B) Statement 2 alone is sufficient, but statement 1 alone is not.
(C) Both statements together are sufficient, but neither alone is sufficient.
(D) Each statement alone is sufficient.
(E) Neither statement is sufficient, even when combined.
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M47-168
02 Jun 2026, 01:15
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GMAT Club Official Solution:
A cyclist followed a two-leg route from a riverside park to a lookout point. If the second leg of the route was twice as long as the first leg, what was the cyclist’s average (arithmetic mean) speed for the entire route?
Let the length of the first leg be d kilometers. Then the length of the second leg is 2d kilometers. So the total distance is:
d + 2d = 3d
The question asks for the cyclist’s average speed for the entire route:
total distance / total time
(1) The cyclist’s average speed was 12 kilometers per hour on the first leg and 24 kilometers per hour on the second leg.
This means the two times are equal, but it does not tell us how long either time was.
For example, if the first leg was 1 kilometer and the second leg was 2 kilometers, and the cyclist spent 1 hour on each leg, then the total distance was 3 kilometers and the total time was 2 hours. The average speed was:
3/2 kilometers per hour
But if the first leg was 2 kilometers and the second leg was 4 kilometers, and the cyclist spent 1 hour on each leg, then the total distance was 6 kilometers and the total time was 2 hours. The average speed was:
3 kilometers per hour
Not sufficient.
Answer: A.
A cyclist followed a two-leg route from a riverside park to a lookout point. If the second leg of the route was twice as long as the first leg, what was the cyclist’s average (arithmetic mean) speed for the entire route?
Let the length of the first leg be d kilometers. Then the length of the second leg is 2d kilometers. So the total distance is:
d + 2d = 3d
The question asks for the cyclist’s average speed for the entire route:
total distance / total time
(1) The cyclist’s average speed was 12 kilometers per hour on the first leg and 24 kilometers per hour on the second leg.
This means the two times are equal, but it does not tell us how long either time was.
For example, if the first leg was 1 kilometer and the second leg was 2 kilometers, and the cyclist spent 1 hour on each leg, then the total distance was 3 kilometers and the total time was 2 hours. The average speed was:
3/2 kilometers per hour
But if the first leg was 2 kilometers and the second leg was 4 kilometers, and the cyclist spent 1 hour on each leg, then the total distance was 6 kilometers and the total time was 2 hours. The average speed was:
3 kilometers per hour
Not sufficient.
Answer: A.
General Discussion
24 May 2026, 23:39
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The answer is A
Given: Journey1 distance is d and return journey is 2d.
To find: the Average speed of whole journey. As=(d+2d)/total time "T" of the journey
1) S1=12 and S2=24 so we can find the average dspeed = 3d/(d/s1+2d/s2).. d in numertor and denominator cancels. hence sufficient
2)Time taken to and fro is the same. so T=2t But we wont know 3d/2t which gives average unless we know either time or speed. hence insufficient.
A is the answer hence
Given: Journey1 distance is d and return journey is 2d.
To find: the Average speed of whole journey. As=(d+2d)/total time "T" of the journey
1) S1=12 and S2=24 so we can find the average dspeed = 3d/(d/s1+2d/s2).. d in numertor and denominator cancels. hence sufficient
2)Time taken to and fro is the same. so T=2t But we wont know 3d/2t which gives average unless we know either time or speed. hence insufficient.
A is the answer hence
