............................. Distance .................... Time ............................ Speed
Day I .................... d ................................. 4 ..................................... \(\frac{d}{4}\) (Let "d" is the distance covered on Day I)
Day II .................. 280-d ........................... 8 ..................................... \(\frac{280-d}{8}\)
Given that \(\frac{d}{4} - \frac{280-d}{8} = 10\)
d = 120
Speed on day II \(= \frac{280-120}{8} = \frac{160}{8} = 20\)
Answer = C
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