............................. Distance .................... Time ............................ Speed

Day I .................... d ................................. 4 ..................................... \(\frac{d}{4}\) (Let "d" is the distance covered on Day I)

Day II .................. 280-d ........................... 8 ..................................... \(\frac{280-d}{8}\)

Given that \(\frac{d}{4} - \frac{280-d}{8} = 10\)

d = 120

Speed on day II \(= \frac{280-120}{8} = \frac{160}{8} = 20\)

Answer = C

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