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Re: A cylindrical vessel of a certain height and radius can hold 30 liters [#permalink]
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Bunuel wrote:
A cylindrical vessel of a certain height and radius can hold 30 liters of water in it when filled to the brim. All the water in the cylindrical vessel is transferred to a spherical vessel. If the height and radius of the cylindrical vessel is the same as the radius of the spherical vessel, what percentage of the capacity of the spherical vessel will remain empty after the transfer?

A. 0%
B. 16.67%
C. 25%
D. 33.33%
E. 50%

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You need to know the following volume formulas.

Cylinder: \(V = πr^2 · h\)

Sphere: \(V = \frac{4}{3} πr^3\)

The height and radius of the cylinder equals the radius of the sphere, so \(r = h\).

Cylinder: \(V = πr^3\)

Sphere: \(V = \frac{4}{3} πr^3\)

You actually don't need to use 30 liters in this problem. You would get the same answer no matter what this value was. When the water is transferred \(\frac{1}{3} πr^3\) will remain unfilled. Therefore, the proportion that is unfilled is

Unfilled: \(\frac{1}{3}πr^3 ÷ \frac{4}{3}πr^3 = \frac{1}{4}\).

Converting this to a percentage, you get (C) 25%.
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Re: A cylindrical vessel of a certain height and radius can hold 30 liters [#permalink]
As the height and radius of the cylindrical vessel is same as the radius of the sphere so r=h
Volume of cylinder thus is πr^3
Volume of sphere is 4/3πr^3
So πr^3 is 75% of the volume of the sphere.
As volume of cylinder / volume of sphere is 3/4 .
Converting to % = (3/4)*100 =75%
So % that is left empty is 100-75 =25%.
So, answer is C

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Re: A cylindrical vessel of a certain height and radius can hold 30 liters [#permalink]
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