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A dealer mixes a pounds of nuts worth b cents per pound with c pounds [#permalink]
Since the dealer mixes
a=1 pounds of nuts worth b=30 cents per pound
and c=2 pounds of nuts at d=15 cents per pound,

he would be selling one pound of this mixture at \(\frac{1*30 + 2*15}{1 + 2} = \frac{60}{3} = 20\) cents

For the dealer to make a profit of 10 cents per pound, he would have to sell the mixture at \(30\) cents.

Evaluating answer options,

(A) (ab + cd)/(a + c) + 10 = 1*30 + 2*15/(1 + 2) + 10 = 30 cents.

Therefore, Option A((ab + cd)/(a + c) + 10) is the price at which the dealer should sell a pound of the mixture.
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Re: A dealer mixes a pounds of nuts worth b cents per pound with c pounds [#permalink]
Type 1:
Quantity: 'a' lbs
Unit Price: 'b' cents/lbs
Total Cost: 'ab' cents

Type 2:
Quantity: 'c' lbs
Unit Price: 'd' cents/lbs
Total Cost: 'cd' cents

Type 1+2:
Net Cost Price: (ab+cd) cents
Net Quantity: (a+c)
Net Unit Price: (ab+cd)/(a+c)

Profit on unit price: 10 cents

Therefore,
Selling Price per unit:
{(ab+cd)/(a+c)} + 10

Ans A

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Re: A dealer mixes a pounds of nuts worth b cents per pound with c pounds [#permalink]
Expert Reply
Bunuel wrote:
A dealer mixes a pounds of nuts worth b cents per pound with c pounds of nuts worth d cents per pound. At what price should he sell a pound of the mixture if he wishes to make a profit of 10 cents per pound?

(A) (ab + cd)/(a + c) + 10

(B) (ab + cd)/(a + c) + 0.1

(C) (b + d)/(a + c) + 10

(D) (b + d)/(a + c) + 0.1

(E) (b + d + 10)/(a + c)


The mixed nuts are worth (ab + cd)/(a + c) cents per pound. Thus if he wants to make a profit of 10 cents per pound, he should sell them for (ab + cd)/(a + c) + 10 cents per pound.

Answer: A
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Re: A dealer mixes a pounds of nuts worth b cents per pound with c pounds [#permalink]
Suggest to modify the question to "At what price should he sell <EACH> pound of the mixture if he wishes to make a profit of 10 cents per pound? " as opposed to "a pound" as the question have a and b variable as well.
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Re: A dealer mixes a pounds of nuts worth b cents per pound with c pounds [#permalink]
Bunuel wrote:
A dealer mixes a pounds of nuts worth b cents per pound with c pounds of nuts worth d cents per pound. At what price should he sell a pound of the mixture if he wishes to make a profit of 10 cents per pound?

(A) (ab + cd)/(a + c) + 10

(B) (ab + cd)/(a + c) + 0.1

(C) (b + d)/(a + c) + 10

(D) (b + d)/(a + c) + 0.1

(E) (b + d + 10)/(a + c)



Price of new mixture = \(\frac{(ab+cd)}{a+c}\)
Therefore to sell at 10 cents higher per pound = Price + 10

Option A
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Re: A dealer mixes a pounds of nuts worth b cents per pound with c pounds [#permalink]
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Re: A dealer mixes a pounds of nuts worth b cents per pound with c pounds [#permalink]
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