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A dealer originally bought 200 identical violins at a total cost of q

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A dealer originally bought 200 identical violins at a total cost of q [#permalink]

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New post 22 Jan 2018, 01:32
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A dealer originally bought 200 identical violins at a total cost of q dollars. If each violin was then sold at 40 percent above the original cost per violin, then in terms of q, at what price did each violin sell?

A. q/5

B. 7q/1000

C. 7q/5

D. 280/q

E. q/200 + 40q

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Re: A dealer originally bought 200 identical violins at a total cost of q [#permalink]

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New post 22 Jan 2018, 01:47
Bunuel wrote:
A dealer originally bought 200 identical violins at a total cost of q dollars. If each violin was then sold at 40 percent above the original cost per violin, then in terms of q, at what price did each violin sell?

A. q/5

B. 7q/1000

C. 7q/5

D. 280/q

E. q/200 + 40q


Since the calculation looks relatively straightforward, we'll just do it.
This is a Precise approach.

The average price per violin is q/200. If this was sold at a 40% increase we get (q/200)*1.4 = 14q/2000 = 7q/1000
(B) is our answer.
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Re: A dealer originally bought 200 identical violins at a total cost of q [#permalink]

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New post 22 Jan 2018, 06:17
Price of each violin C.P.= q/200. S.P= 1.4 times C.P. Therefore selling price= 1.4*q/200=7q/1000. Ans-B.

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Re: A dealer originally bought 200 identical violins at a total cost of q [#permalink]

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New post 22 Jan 2018, 08:37
Bunuel wrote:
A dealer originally bought 200 identical violins at a total cost of q dollars. If each violin was then sold at 40 percent above the original cost per violin, then in terms of q, at what price did each violin sell?

A. q/5

B. 7q/1000

C. 7q/5

D. 280/q

E. q/200 + 40q


Ans: B

Price of each violin = q / 200

40% of violin cost = 40 % of (q/200) = q/500

Total cost = (q/200) + (q/500) = 7q/1000
option B
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Re: A dealer originally bought 200 identical violins at a total cost of q [#permalink]

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New post 22 Jan 2018, 08:42
Bunuel wrote:
A dealer originally bought 200 identical violins at a total cost of q dollars. If each violin was then sold at 40 percent above the original cost per violin, then in terms of q, at what price did each violin sell?

A. q/5

B. 7q/1000

C. 7q/5

D. 280/q

E. q/200 + 40q


Cost of Each Violin is \(q/200\).Therefore, each sold will be \((7/5)(q/200) = 7q/1000\).
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Re: A dealer originally bought 200 identical violins at a total cost of q [#permalink]

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New post 22 Jan 2018, 08:59
Bunuel wrote:
A dealer originally bought 200 identical violins at a total cost of q dollars. If each violin was then sold at 40 percent above the original cost per violin, then in terms of q, at what price did each violin sell?

A. q/5

B. 7q/1000

C. 7q/5

D. 280/q

E. q/200 + 40q

CP of each Violin = \(\frac{q}{200}\)
Sp of Each Violin = \(\frac{q}{200}*\frac{140}{100}\)

Or, Sp of Each Violin = \(\frac{q}{200}*\frac{7}{5}\)

Or, Sp of Each Violin = \(\frac{7q}{1000}\), answer will be (B)

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Re: A dealer originally bought 200 identical violins at a total cost of q [#permalink]

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New post 23 Jan 2018, 08:54
Bunuel wrote:
A dealer originally bought 200 identical violins at a total cost of q dollars. If each violin was then sold at 40 percent above the original cost per violin, then in terms of q, at what price did each violin sell?

A. q/5

B. 7q/1000

C. 7q/5

D. 280/q

E. q/200 + 40q



The original cost per violin is q/200, so the the selling price per violin was:

1.4 x q/200 = 1.4q/200 = 14q/2000 = 7q/1000

Answer: B
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Re: A dealer originally bought 200 identical violins at a total cost of q   [#permalink] 23 Jan 2018, 08:54
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A dealer originally bought 200 identical violins at a total cost of q

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