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02 Dec 2014, 09:15
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
92% (01:45) correct
8%
(02:18)
wrong
based on 216
sessions
History
Date
Time
Result
Not Attempted Yet
Tough and Tricky questions: Mixture Problems.
A drink holding 6 ounces of an alcoholic drink that is 1 part rum to 2 parts coke is added to a jug holding 32 ounces of an alcoholic drink that is 1 part rum to 3 parts coke. What is the ratio of rum to coke in the resulting mixture?
A) 2:5
B) 5:14
C) 3:5
D) 4:7
E) 14:5
Kudos for a correct solution.
Source: Chili Hot GMAT
intheend14
GMAT 1: 740 Q49 V41
Posts: 127
02 Dec 2014, 10:05
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The first drink has 6 oz, which are 2 oz rum and 4 oz coke. The second drink is 32 oz, which are 8 oz rum and 24 oz coke. The resulting mixture is then 38 oz (10 oz rum and 28 oz coke). Overall, this is 10 oz rum: 28 oz coke, which is a 5:14 ratio.
Answer is B
Answer is B
02 Dec 2014, 20:21
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Answer = B) 5:14
........................ Rum ..................... Coke ................. Total
First Drink ........... 2 ............................ 4 ..................... 6 (Ratio 1:2)
Second Drink ....... 8 ............................. 24 ................... 32 (Ratio 1:3)
Total .................. 10 ............................. 28 .................... 38
Ratio = 10:28 = 5:14
........................ Rum ..................... Coke ................. Total
First Drink ........... 2 ............................ 4 ..................... 6 (Ratio 1:2)
Second Drink ....... 8 ............................. 24 ................... 32 (Ratio 1:3)
Total .................. 10 ............................. 28 .................... 38
Ratio = 10:28 = 5:14
