The first drink has 6 oz, which are 2 oz rum and 4 oz coke. The second drink is 32 oz, which are 8 oz rum and 24 oz coke. The resulting mixture is then 38 oz (10 oz rum and 28 oz coke). Overall, this is 10 oz rum: 28 oz coke, which is a 5:14 ratio.

Answer is B

Answer = B) 5:14

........................ Rum ..................... Coke ................. Total

First Drink ........... 2 ............................ 4 ..................... 6 (Ratio 1:2)

Second Drink ....... 8 ............................. 24 ................... 32 (Ratio 1:3)

Total .................. 10 ............................. 28 .................... 38


Ratio = 10:28 = 5:14

6 ounces = 2 rum, 4coke
32 ounces = 8 rum 24 coke
total
10 rum 28 coke = 5:14

The correct answer is B.
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Let's solve it in a different way

Add 6 ounces + 32 ounces = 38

So my ratio a:b will be such that a + b divides 38 equally

Looking at options we can see 14+5 = 19
But we have two options utilizing those numbers.

But if you look the ratios 1:2 of mixture 1 and 1:3 of mixture 2 then it's certain that coke will be higher

So correct answer should be 5:14 as ratio asked and given is rum : coke

Option B



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(⅓ x 6 + ¼ x 32)/(⅔ x 6 + ¾ x 32)

(2 + 8)/(4 + 24)

10/28 = 5/14

Alternate Solution:

We start with 6 ounces of a drink that is ⅓ rum. We add it to 32 ounces that is ¼ rum. The result is a mixture of 6 + 32 = 38 ounces of x percent of rum.

Putting this information into an equation, we have:

6(⅓) + 32(¼) = 0.38x

2 + 8 = 0.38x

10/0.38 = x

Since the percent of rum is 10/0.38, then the percent of coke is 28/0.38.

Thus, we can express the ratio of rum to coke as:

(10/0.38)/(28/0.38) = 10/28 = 5/14

Answer: B
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First the resultant mixture is 38 ounces.

First we will find rum and get coke weight by subtracting from mix.

From first 6 ounces , rum:coke = 1:2

So, rum is 2 ounces in this mix.

From second 32 , rum : coke = 1:3

So, rum is 8 ounces in this mix.

Total rum in mix = 10

So total coke in mix = 28

Ratio = 10:28 = 5/14 , B is correct

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