A toy factory has four assembly machines that operate at constant rates. Machine C takes 3 times as long as machine A to assemble a given number of items. Machine B takes 4 times as long as machine C and twice as long as machine D. How long would it take machine A alone to assemble the same number of items that machines B, C, and D working together can assemble in 1 hour?A. 20 minutes
B. 35 minutes
C. 45 minutes
D. 51 minutes
E. 60 minutes
Let machine A’s rate be
12 units per hour.
Then:
- C takes 3 times as long as A, so C’s rate is 4 units per hour.
- B takes 4 times as long as C, so B’s rate is 1 unit per hour.
- B takes twice as long as D, so D is twice as fast as B. Thus D’s rate is 2 units per hour.
Together, B, C, and D assemble:
1 + 4 + 2 = 7 units per hour
Machine A assembles 12 units per hour, so the time A needs to assemble 7 units is:
7/12 hour = 35 minutes
Answer: B.
errornisi
Hi,
It says "
Machine C takes 3 times as long as machine A" so doesn't that mean C= 1/3A or A=3C?
Thanks in advance.It depends on what A and C denote.
If A and C denote
times, then C = 3A, because Machine C takes 3 times as long as Machine A.
If A and C denote
rates, then C = A/3, because taking 3 times as long means working at one-third the rate.