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01 May 2026, 05:31
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
62% (02:00) correct
38%
(02:20)
wrong
based on 114
sessions
History
Date
Time
Result
Not Attempted Yet
A five-element code is to be created from the letters A, B, and C and the digits 1, 2, 3, and 4. If no more than one letter or digit can appear sequentially and elements cannot be repeated in a code, how many such codes can be created?
(A) 24
(B) 48
(C) 72
(D) 144
(E) 216
Source: Marty Murray Coaching
(A) 24
(B) 48
(C) 72
(D) 144
(E) 216
Source: Marty Murray Coaching
01 May 2026, 06:23
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3 letters 4 digits
Consecutive letter or consecutive digit
Repeat elements
First is alphabet then digit
34231 = 72
First is digit then alphabet
43322. = 144
Add = 216
Ans Opt E
Hope it helps.
Hi MartyMurray
It would be helpful to know if my approach is logically correct. Also, if any, I want to know other approach to this question.
First is alphabet then digit
34231 = 72
First is digit then alphabet
43322. = 144
Add = 216
Ans Opt E
Hope it helps.
Hi MartyMurray
It would be helpful to know if my approach is logically correct. Also, if any, I want to know other approach to this question.
MartyMurray
01 May 2026, 06:37
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adconsectetur
Your approach is spot on, and that's how I would do it too.
