Teams can be formed as 2E-3W , 3E-2W , 4E-W and 5E
Possible ways to make a team 2E-3W = 6c2 * 6c3 = 300
Possible ways to make a team 3E-2W = 6c3 * 6c2 = 300
Possible ways to make a team 4E-W = 6c4 * 6c1 = 90
Possible ways to make a team 5E = 6c5 = 6
Number of ways to select a team of 5 out of 12 people = 12c5
=12!/(7!*5!)
= 792
Probability that the team will contain at least 2 East All Stars
= (300+300+90+6) / 792
=696/792
= 29/33
Answer A
Alternatively we can also calculate the number of possible ways to make a team of 5W and E-4W .
Possible ways to make a team 5W = 6c5 = 6
Possible ways to make a team E-4W = 6c1 * 6c4 = 90
Probability that the team will contain at least 2 East All Stars = 1 - (96/792)
= 29/33
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