GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 20 Apr 2019, 19:49

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# A flat triangular cornfield has the dimensions shown in the figure abo

Author Message
TAGS:

### Hide Tags

Intern
Joined: 11 Dec 2009
Posts: 4
A flat triangular cornfield has the dimensions shown in the figure abo  [#permalink]

### Show Tags

Updated on: 24 Feb 2015, 14:53
3
00:00

Difficulty:

45% (medium)

Question Stats:

66% (01:51) correct 34% (01:46) wrong based on 145 sessions

### HideShow timer Statistics

Attachment:

gmat190507-1-735112.jpg [ 9.55 KiB | Viewed 4350 times ]
A flat triangular cornfield has the dimensions shown in the figure above. If y^2 = 2, what is the area of the field in square miles?

(A) 1/4
(B) √3/4
(C) 1/2
(D) √3/2
(E) 1

Originally posted by phangureh on 24 Dec 2009, 13:11.
Last edited by Bunuel on 24 Feb 2015, 14:53, edited 1 time in total.
Renamed the topic, edited the question and added the OA.
Math Expert
Joined: 02 Sep 2009
Posts: 54376
A flat triangular cornfield has the dimensions shown in the figure abo  [#permalink]

### Show Tags

25 Dec 2009, 05:53
1
4
phangureh wrote:

A flat triangular cornfield has the dimensions shown in the figure above. If y^2 = 2, what is the area of the field in square miles?

(A) 1/4
(B) √3/4
(C) 1/2
(D) √3/2
(E) 1

$$Area=\frac{Base*Heigt}{2}$$

$$Hypotenuse=\sqrt{2}$$

$$Base = \frac{y}{2}=\frac{\sqrt{2}}{2}$$

$$Height=\sqrt{\sqrt{2}^2-(\frac{\sqrt2}{2})^2}=\sqrt{2-\frac{1}{2}}=\frac{\sqrt3}{\sqrt2}$$ (Pythagora's)

$$Area=\frac{Base*Heigt}{2}=\frac{1}{2}*\frac{\sqrt{2}}{2}*\frac{\sqrt3}{\sqrt2}=\frac{\sqrt{3}}{4}$$
_________________
##### General Discussion
Senior Manager
Joined: 30 Aug 2009
Posts: 266
Location: India
Concentration: General Management
Re: A flat triangular cornfield has the dimensions shown in the figure abo  [#permalink]

### Show Tags

24 Dec 2009, 22:25
phangureh wrote:
Anyone know how to do this?

1) A flat triangular cornfield has the dimensions shown in the figure above. If y^2 = 2, what is the area of the field in square miles?

The figure is a right triangle with the hypotenuse Y miles and one of the legs is Y/2 miles

Answer is square root 3 / 4

can you please post the figure in the question.....not able to view it
Senior SC Moderator
Joined: 22 May 2016
Posts: 2642
A flat triangular cornfield has the dimensions shown in the figure abo  [#permalink]

### Show Tags

15 May 2017, 09:07
1
phangureh wrote:
Attachment:
gmat190507-1-735112.jpg
A flat triangular cornfield has the dimensions shown in the figure above. If y^2 = 2, what is the area of the field in square miles?

(A) 1/4
(B) √3/4
(C) 1/2
(D) √3/2
(E) 1

If a right triangle's hypotenuse is twice the length of the shorter leg (here, hypotenuse = y and shorter leg = $$\frac{y}{2}$$), it is a 30-60-90 triangle with side ratio x : $$\sqrt{3}$$x : 2x

We also know that $$y^2$$=2

Take the square root of both sides to get y = $$\sqrt{2}$$

Short leg is $$\frac{y}{2}$$ = $$\frac{√2}{2}$$

Longer leg is $$\sqrt{3}$$*$$\frac{√2}{2}$$ = $$\frac{√6}{2}$$

Area = (b*h)/2

$$\frac{√6}{2}$$ * $$\frac{√2}{2}$$ divided by 2

$$\frac{√12}{4}$$ = $$\frac{(2√3)}{4}$$ divided by 2

$$\frac{(2√3)}{4}$$ ÷ 2 = $$\frac{(2√3)}{8}$$= $$\frac{√3}{4}$$

_________________
Listen, are you breathing just a little, and calling it a life?
-- Mary Oliver

For practice SC questions with official explanations that were posted and moderated by the SC Team,
go to SC Butler here: https://gmatclub.com/forum/project-sc-butler-get-2-sc-questions-everyday-281043.html
Non-Human User
Joined: 09 Sep 2013
Posts: 10564
Re: A flat triangular cornfield has the dimensions shown in the figure abo  [#permalink]

### Show Tags

10 Apr 2019, 08:26
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
Re: A flat triangular cornfield has the dimensions shown in the figure abo   [#permalink] 10 Apr 2019, 08:26
Display posts from previous: Sort by