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odd digits {0,2,6,8}
even digits {3,5,7,9}
Let safe code be WXYZ
Prob of getting 1 odd digit in safe number position W: 1/2
Prob of getting 2 odd digits in safe number W and X: (1/2)^2
...
Prob of getting 4 odd digits(all) in safe number position W, X, Y and Z: (1/2)^4
Prob of getting at least 1 even is equal to 1- prob(all odd)
1 - 1/16 = 15/16
I think you mixed up the sample set where total digits should be 8(as shown in my odd/even sample set) as opposed to 7.
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