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27 Aug 2022, 04:45
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
76% (01:22) correct
24%
(01:29)
wrong
based on 45
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Not Attempted Yet
A fraternity wants to enroll members of the college rowing team as members. The result of the fraternity's effort to recruit new members from the rowing team exceeds the fraternity's expectation by 20 percent. Assuming that the rowing team admits only males, what is the total number of people on the rowing team?
(1) The goal was to enroll 15 percent of the members of the rowing team.
(2) The number of rowing team members enrolling as new fraternity members was 40.
(1) The goal was to enroll 15 percent of the members of the rowing team.
(2) The number of rowing team members enrolling as new fraternity members was 40.
02 Sep 2022, 23:17
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Bunuel
We need to know the # of members of the rowing team.
(1) The goal was to enroll 15 percent of the members of the rowing team.
We cannot tell anything about the # of members of the rowing team. We can only tell that more than this # was enrolled.
INSUFF.
(2) The number of rowing team members enrolling as new fraternity members was 40
This is \(20\% \) more than intended. Hence intended number was \(80\%\) of \(40 = 32\)
Hence we know the intended number for enrollement. Still we cannot tell about the # of members of the rowing team.
INSUFF.
1+2
From (2) we know intended # is \(32\) and from (1) we know that \(32\) is \(15\%\) of the members of the rowing team.
so if \(x\) is the # of members of the rowing team , we can write \(15 \%\) of \(x = 32\)
\(.15*x=32\)
\(x= \frac{3200}{15}\)
SUFF.
Ans C
Hope it's clear.
(P.S.- Unless I have messed up somewhere, # of members should have come out as an integer.)
26 Oct 2022, 03:22
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The question stem gives us relation between Expected and Actual Recruitment. But the statement one is about Goal which we are not sure if it is equal to expected number of not. Please help in solving this.
