A full glass of lemonade is a mixture of 20% lime juice and 80% soda.

Question

A full glass of lemonade is a mixture of 20% lime juice and 80% soda. The contents of the glass are poured into a pitcher that is 200% bigger than the glass. The remainder of the pitcher is filled with 16 litres of water. What was the original volume of lime juice in the mixture?

(A) 1.6 litres
(B) 3.2 litres
(C) 4.8 litres
(D) 6.4 litres
(E) 8 litres

Show Answer

Official Answer

A

(A) 1.6 litres
(B) 3.2 litres
(C) 4.8 litres
(D) 6.4 litres
(E) 8 litres

rocky620 · Accepted Answer

Let the Original Volume be x liters.
After 200% increase new volume = x+2x = 3x

Also, the increase in volume is filled with 16ltrs of water, i.e. 2x = 16. So, x=8ltrs

Lime juice in original volume = 20% of x => .2*8=1.6ltrs.

Option A.

adewale223 · Answer

Let orginal volume of mixture be x

Lime juice 0.2x

Soda 0.8x

Volume of pitcher is 3x

Volume left after mixture was poured

3x - x = 2x

Therefore 2x = 16

So x = 8

Original volume of lime juice=

0.2 x 8 = 1.6
GMAT quant instructor Lagos Nigeria

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MathRevolution · Answer

Let the original volume of glass is 100 liters.

=> Lime juice = 20% = 20 litres

=> Soda = 80% = 80 litres

Then pitcher is 200% bigger =  \frac{200}{100} * 100 = 200  litres.

Total volume = 100 + 200 = 300 liters

=> Volume of Pitcher - Volume of transferred glass content = Remainder

300 litres - 100 litres = 200 liters

Now, 200 liters of the remainder in our equation equal to 16 liters given in the question.

=> 2 * 100 litres = 16 litres

=> So, 100 liters should be equal to 8 liters.

In 8 litres of glass, lime juice is 20% =  \frac{20 }{ 100} * 8 = 1.6  litres.

Answer A

APOGEE · Answer

not very big eqns are needed here, you can assume values starting from 5 ltrs as ratio is in multiple of 5 , do 2-3 values and you will fetch 8*3=24 -16=8 ,the required value it will save you from cumbersome eqns making

Paras96 · Answer

A full glass of lemonade is a mixture of 20% lime juice and 80% soda. The contents of the glass are poured into a pitcher that is 200% bigger than the glass. The remainder of the pitcher is filled with 16 litres of water. What was the original volume of lime juice in the mixture?

(A) 1.6 litres
(B) 3.2 litres
(C) 4.8 litres
(D) 6.4 litres
(E) 8 litres

Show Answer

Official Answer

A

Let the volume of glass = v
then, the volume of lemonade class = 3v
Given that, the volume of lemonade class - the volume of glass = 16 litre 
=> 2v = 16
=> v = 8

therefore volume of lime juice = (2/10)*8 = 1.6 Litre

Hence A

shishirtu · Answer

Glass> L:S = 1:4 = 5 parts
Pitcher> L:S:W = 1:4: 10  =  15  parts (Final mixture is 200% (or, 10parts) more than 5 parts and those 10 parts is filled with water)
10p water= 16L
1p water=  1.6L

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A full glass of lemonade is a mixture of 20% lime juice and 80% soda.

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