I have troible understanding, how is it that we assume that manufacturer can start producing 4 pieces on furniture on 1st day or 17th day only, what if he started producing 4 pieces on 2nd day then median will (4+3)/2, if 3rd day median will be (4+4)/2.
Additionally the question also doesnt specify that manufacturer has gradualy increased/ decreased his production, he can also produce 3 on eventh day and 4 on oddth day
akshayferdi
Could someone assist with the explanation for this question? Didn't follow how to answer with the corrected problem statement 2
A furniture manufacturer produced at least 3 cabinets each day for the past 30 working days. What was the median number of cabinets produced daily by the manufacturer for the past 30 working days?Given that at least 3 cabinets were produced daily, the minimum total production is 3 cabinets/day * 30 days = 90 cabinets. To find the median of an even number of terms (30 days in this case), we average the two middle terms once the terms are arranged in order.
(1) For the past 30 working days, the manufacturer produced at most 6 cabinets each day.
If 6 cabinets were produced each day, the median would be 6. However, if 3 cabinets were produced for 29 days and 6 cabinets on one day, the median would be 3.
Not sufficient.
(2) For the past 30 working days, the manufacturer produced a total of 104 cabinets.
We already know that the minimum production over this period, with at least 3 cabinets produced each day, is 90 cabinets. This implies that there are 14 additional cabinets to account for in the total production.
Initially, our set of daily productions looks like this:
{3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3}
To find the median, we need to determine if adding the extra 14 cabinets can change the middle values (15th and 16th terms) in this set. Even if we distribute these additional cabinets in the most balanced way possible, by adding 1 cabinet to 14 of the days, the set becomes:
{3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4}
In this configuration, the 15th and 16th terms, which determine the median, remain unchanged at 3. Therefore, regardless of how the additional 14 cabinets are distributed, the median number of cabinets produced daily remains 3.
Sufficient.
Answer: B.