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kevincan
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jaynayak
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MA
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kevincan
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Any more comments before I give the OA?
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ps_dahiya
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I go with E

Total hours = 168

St1: Time interval between spouts must be between 6 [24/(3+1)] and 12 [24/(3-1)].
Maximum spouts = 168/6 = 28
Min spouts = (168 - 12)/12 = 13
INSUFF

St2: Same as above: INSUFF

Together:
Means it spouted 6 times in 48 hours.
Time interval between spouts must be between 48/7 [48/(6+1)] and 48/5 [48/(6-1)].

Maximun spouts = 168/(48/7) = 24.5
Minimum spouts = (168-48/5)/(48/5) = 16.5: INSUFF
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kevincan
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Excellent! Or we can can say that it sprouts 3 times on 2 consecutive days, the average number of sprouts per day must be greater than 2.5.

Yours is the OE
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MA
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why are you taking out 1 here???? :roll:
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MA
why are you taking out 1 here???? :roll:

I am taking the worst case scenario. For example we are starting at 00:00 hours but if geyser sprouted just 1 second before we started our time i.e 23:59:59 previous day. Then there will be one less spout.



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