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A girl at point X walks 1 mile east, then 2 miles north then 1 mile ea

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A girl at point X walks 1 mile east, then 2 miles north then 1 mile ea [#permalink]

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A girl at point X walks 1 mile east, then 2 miles north then 1 mile east, then 1 mile north, then 1 mile east, then 1 mile north to arrive at point Y. From point Y, what is the shortest distance to point X ?


(A) 7 miles
(B) 6 miles
(C) 5 miles
(D) 2.5 miles
(E) 1 mile

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Re: A girl at point X walks 1 mile east, then 2 miles north then 1 mile ea [#permalink]

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New post 05 Feb 2018, 08:20
Bunuel wrote:
A girl at point X walks 1 mile east, then 2 miles north then 1 mile east, then 1 mile north, then 1 mile east, then 1 mile north to arrive at point Y. From point Y, what is the shortest distance to point X ?


(A) 7 miles
(B) 6 miles
(C) 5 miles
(D) 2.5 miles
(E) 1 mile


Total East distance = 3 miles (3 X 1 mile east)
Total North distance= 4 miles (2+1+1 north)

this is triangle with hyp as the shortest distance , so by Pythagorean triplets hyp= 5 miles

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A girl at point X walks 1 mile east, then 2 miles north then 1 mile ea [#permalink]

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New post 05 Feb 2018, 08:21
Attachment:
From X to Y.png
From X to Y.png [ 1.96 KiB | Viewed 285 times ]


From the figure, we have the path the girl has taken to get from X to Y.
Since, the three triangles are right angled triangles, the sum of their
hypotenuse is the shortest distance to get from the point X to Y.

The hypotenuse of the right triangle with sides 1 and 2 is \(\sqrt{1+4} = \sqrt{5}\)

The hypotenuse of the other two isosceles right angles triangles(both sides = 1) is \(\sqrt{1+1} = \sqrt{2}\)

The shortest distance is \(\sqrt{5} + 2*\sqrt{2}= 2.2 + 2*1.4 = 5\) (Option C)
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Re: A girl at point X walks 1 mile east, then 2 miles north then 1 mile ea [#permalink]

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New post 06 Feb 2018, 18:30
Bunuel wrote:
A girl at point X walks 1 mile east, then 2 miles north then 1 mile east, then 1 mile north, then 1 mile east, then 1 mile north to arrive at point Y. From point Y, what is the shortest distance to point X ?


(A) 7 miles
(B) 6 miles
(C) 5 miles
(D) 2.5 miles
(E) 1 mile


Image

We can depict the route from point X to point Y by the diagram above. We see that the shortest distance between X and Y is the dotted segment. Since the girl really travels 3 miles east and 4 miles north, we can create a right triangle such that the hypotenuse is the dotted segment and two legs are 3 and 4 (blue segments). Since this is a right triangle, we can use the Pythagorean theorem to find the length of the hypotenuse or by recognizing this triangle is a 3-4-5 right triangle. Therefore, we see that the shortest distance between X and Y is 5 miles.

Answer: C
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Re: A girl at point X walks 1 mile east, then 2 miles north then 1 mile ea   [#permalink] 06 Feb 2018, 18:30
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