renjana wrote:
A hiking club’s trip will be cancelled if, on the first day of the trip, the temperature is less than 20 degrees Fahrenheit or it is snowing. If there is a 15% chance that temperatures will be below 20 degrees and a 60% chance that it will not snow, what is the likelihood that the trip will be cancelled?
A. 40%
B. 49%
C. 55%
D. 66%
E. 75%
P(Trip cancelled )= P(Temp less than 20) +(OR) P(Snowing)
(P(Temp less than 20) = 15/100
P(Snowing) = 40/100
P(Trip cancelled )= 55/100
Please correct me if i am wrong !
The question is looking for the likelihood in which the trip will be canceled.
A: Temp less than 20 =
15%B: Snowing =
40%not A: Temp not less than 20 =
85%not B: Not Snowing =
60%The occurrence of A & B are parallel and Happening of
either of them will cancel the trip.
The trip is going to be canceled under the following conditions:
A*B + A*(not B) + (not A)*B :
15% * 40% + 15% * 60% + 85% * 40% = 49%
Shortcut method: Find the probability in which trip will happen and subtract from the total set of events, i.e.,
1 - (when trip won't be canceled) : 1 - (not A)*(not B)
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