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aeros232
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A house seller can deduct 5 percent from the total sales 29 Sep 2012, 13:32
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E
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A house seller can deduct 5 percent from the total sales value. If he has sold 5 houses, and the price of two houses is between $150,000 and $250,000, one of them is $300,000 house, two houses are between $500,000 and 750,000, what is the range of his revenue?

A. 450000
B. 510000
C. 570000
D. 660000
E. 780000

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E
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A house seller can deduct 5 percent from the total sales 30 Sep 2012, 00:24
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how m i solving it..m unable to get the ans :D

i did like this..where m i wrong??

First I consider , least value of first 2 homes which is 150,000..and least value of last two homes 500,000..

150,000+150,000+300000+500000+500000=1600,000

then I have taken max value of first two houses. 250,000, and max value of last two houses, which 750,000...

250,000+250,000+300,000+750,000+750,000=2300,000

1600,000*.05=80,000

2300,000*.05=115,000

1150000-80,000=35000..

i got 35000 ans..bt not any option given..
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A house seller can deduct 5 percent from the total sales 30 Sep 2012, 04:27
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Let the first house be sold for 150,000.
Let the 5th house be sold for 750,000.

Difference is 600000
5% of 600000 is 30000 = 570000

Ans: C
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A house seller can deduct 5 percent from the total sales 30 Sep 2012, 08:00
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sanjoo
how m i solving it..m unable to get the ans :D

i did like this..where m i wrong??

First I consider , least value of first 2 homes which is 150,000..and least value of last two homes 500,000..

150,000+150,000+300000+500000+500000=1600,000

then I have taken max value of first two houses. 250,000, and max value of last two houses, which 750,000...

250,000+250,000+300,000+750,000+750,000=2300,000

1600,000*.05=80,000

2300,000*.05=115,000

1150000-80,000=35000..

i got 35000 ans..bt not any option given..
Show more


Hi, you are almost OK. However, the range is for the total revenue, not for the discounts.

(In the example above, I will simplify to smaller numbers)

(1) 2(150)+300+2(500) = 1600
1600*0.95=1520 (Revenue considering the minimum values with the discount)

(2) 2(250)+300+2(750) = 2300 (Revenue considering the maximum values without the discount)

So, the the revenue range could be = 2300 - 1520 = 780 (Answ E)
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A house seller can deduct 5 percent from the total sales 30 Sep 2012, 12:34
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aeros232
sanjoo
how m i solving it..m unable to get the ans :D

i did like this..where m i wrong??

First I consider , least value of first 2 homes which is 150,000..and least value of last two homes 500,000..

150,000+150,000+300000+500000+500000=1600,000

then I have taken max value of first two houses. 250,000, and max value of last two houses, which 750,000...

250,000+250,000+300,000+750,000+750,000=2300,000

1600,000*.05=80,000

2300,000*.05=115,000

1150000-80,000=35000..

i got 35000 ans..bt not any option given..


Hi, you are almost OK. However, the range is for the total revenue, not for the discounts.

(In the example above, I will simplify to smaller numbers)

(1) 2(150)+300+2(500) = 1600
1600*0.95=1520 (Revenue considering the minimum values with the discount)

(2) 2(250)+300+2(750) = 2300 (Revenue considering the maximum values without the discount)

So, the the revenue range could be = 2300 - 1520 = 780 (Answ E)
Show more


R u sure?? its E?
what i think to get maximum range..we should make another mean 2300 should be taken minimum.
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A house seller can deduct 5 percent from the total sales 25 Nov 2012, 20:17
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sanjoo
aeros232
sanjoo
how m i solving it..m unable to get the ans :D

i did like this..where m i wrong??

First I consider , least value of first 2 homes which is 150,000..and least value of last two homes 500,000..

150,000+150,000+300000+500000+500000=1600,000

then I have taken max value of first two houses. 250,000, and max value of last two houses, which 750,000...

250,000+250,000+300,000+750,000+750,000=2300,000

1600,000*.05=80,000

2300,000*.05=115,000

1150000-80,000=35000..

i got 35000 ans..bt not any option given..


Hi, you are almost OK. However, the range is for the total revenue, not for the discounts.

(In the example above, I will simplify to smaller numbers)

(1) 2(150)+300+2(500) = 1600
1600*0.95=1520 (Revenue considering the minimum values with the discount)

(2) 2(250)+300+2(750) = 2300 (Revenue considering the maximum values without the discount)

So, the the revenue range could be = 2300 - 1520 = 780 (Answ E)


R u sure?? its E?
what i think to get maximum range..we should make another mean 2300 should be taken minimum.
Show more

Sorry but why didn t you deducted from the 2300 the 115???
Thus the range is 665,000.
The answer is def not E

Please give some feedback,
Thanks

Posted from GMAT ToolKit

Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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