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A house seller can deduct 5 percent from the total sales

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Intern
Joined: 04 Sep 2009
Posts: 43

Kudos [?]: 82 [0], given: 9

A house seller can deduct 5 percent from the total sales [#permalink]

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29 Sep 2012, 13:32
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23% (00:00) correct 77% (01:53) wrong based on 13 sessions

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A house seller can deduct 5 percent from the total sales value. If he has sold 5 houses, and the price of two houses is between \$150,000 and \$250,000, one of them is \$300,000 house, two houses are between \$500,000 and 750,000, what is the range of his revenue?

A. 450000
B. 510000
C. 570000
D. 660000
E. 780000
[Reveal] Spoiler: OA

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Aeros
"Why are you trying so hard to fit in when you were born to stand out?"
"Do or do not. There is no 'try'..."

Kudos [?]: 82 [0], given: 9

Senior Manager
Joined: 06 Aug 2011
Posts: 388

Kudos [?]: 238 [0], given: 82

Re: A house seller can deduct 5 percent from the total sales [#permalink]

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30 Sep 2012, 00:24
how m i solving it..m unable to get the ans :D

i did like this..where m i wrong??

First I consider , least value of first 2 homes which is 150,000..and least value of last two homes 500,000..

150,000+150,000+300000+500000+500000=1600,000

then I have taken max value of first two houses. 250,000, and max value of last two houses, which 750,000...

250,000+250,000+300,000+750,000+750,000=2300,000

1600,000*.05=80,000

2300,000*.05=115,000

1150000-80,000=35000..

i got 35000 ans..bt not any option given..
_________________

Bole So Nehal.. Sat Siri Akal.. Waheguru ji help me to get 700+ score !

Kudos [?]: 238 [0], given: 82

Intern
Joined: 02 Feb 2012
Posts: 29

Kudos [?]: 14 [0], given: 35

GPA: 4
Re: A house seller can deduct 5 percent from the total sales [#permalink]

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30 Sep 2012, 04:27
Let the first house be sold for 150,000.
Let the 5th house be sold for 750,000.

Difference is 600000
5% of 600000 is 30000 = 570000

Ans: C

Kudos [?]: 14 [0], given: 35

Intern
Joined: 04 Sep 2009
Posts: 43

Kudos [?]: 82 [1], given: 9

Re: A house seller can deduct 5 percent from the total sales [#permalink]

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30 Sep 2012, 08:00
1
KUDOS
sanjoo wrote:
how m i solving it..m unable to get the ans :D

i did like this..where m i wrong??

First I consider , least value of first 2 homes which is 150,000..and least value of last two homes 500,000..

150,000+150,000+300000+500000+500000=1600,000

then I have taken max value of first two houses. 250,000, and max value of last two houses, which 750,000...

250,000+250,000+300,000+750,000+750,000=2300,000

1600,000*.05=80,000

2300,000*.05=115,000

1150000-80,000=35000..

i got 35000 ans..bt not any option given..

Hi, you are almost OK. However, the range is for the total revenue, not for the discounts.

(In the example above, I will simplify to smaller numbers)

(1) 2(150)+300+2(500) = 1600
1600*0.95=1520 (Revenue considering the minimum values with the discount)

(2) 2(250)+300+2(750) = 2300 (Revenue considering the maximum values without the discount)

So, the the revenue range could be = 2300 - 1520 = 780 (Answ E)
_________________

Aeros
"Why are you trying so hard to fit in when you were born to stand out?"
"Do or do not. There is no 'try'..."

Kudos [?]: 82 [1], given: 9

Senior Manager
Joined: 06 Aug 2011
Posts: 388

Kudos [?]: 238 [0], given: 82

Re: A house seller can deduct 5 percent from the total sales [#permalink]

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30 Sep 2012, 12:34
aeros232 wrote:
sanjoo wrote:
how m i solving it..m unable to get the ans :D

i did like this..where m i wrong??

First I consider , least value of first 2 homes which is 150,000..and least value of last two homes 500,000..

150,000+150,000+300000+500000+500000=1600,000

then I have taken max value of first two houses. 250,000, and max value of last two houses, which 750,000...

250,000+250,000+300,000+750,000+750,000=2300,000

1600,000*.05=80,000

2300,000*.05=115,000

1150000-80,000=35000..

i got 35000 ans..bt not any option given..

Hi, you are almost OK. However, the range is for the total revenue, not for the discounts.

(In the example above, I will simplify to smaller numbers)

(1) 2(150)+300+2(500) = 1600
1600*0.95=1520 (Revenue considering the minimum values with the discount)

(2) 2(250)+300+2(750) = 2300 (Revenue considering the maximum values without the discount)

So, the the revenue range could be = 2300 - 1520 = 780 (Answ E)

R u sure?? its E?
what i think to get maximum range..we should make another mean 2300 should be taken minimum.
_________________

Bole So Nehal.. Sat Siri Akal.. Waheguru ji help me to get 700+ score !

Kudos [?]: 238 [0], given: 82

Intern
Joined: 22 Oct 2012
Posts: 17

Kudos [?]: 1 [0], given: 7

Re: A house seller can deduct 5 percent from the total sales [#permalink]

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25 Nov 2012, 20:17
sanjoo wrote:
aeros232 wrote:
sanjoo wrote:
how m i solving it..m unable to get the ans :D

i did like this..where m i wrong??

First I consider , least value of first 2 homes which is 150,000..and least value of last two homes 500,000..

150,000+150,000+300000+500000+500000=1600,000

then I have taken max value of first two houses. 250,000, and max value of last two houses, which 750,000...

250,000+250,000+300,000+750,000+750,000=2300,000

1600,000*.05=80,000

2300,000*.05=115,000

1150000-80,000=35000..

i got 35000 ans..bt not any option given..

Hi, you are almost OK. However, the range is for the total revenue, not for the discounts.

(In the example above, I will simplify to smaller numbers)

(1) 2(150)+300+2(500) = 1600
1600*0.95=1520 (Revenue considering the minimum values with the discount)

(2) 2(250)+300+2(750) = 2300 (Revenue considering the maximum values without the discount)

So, the the revenue range could be = 2300 - 1520 = 780 (Answ E)

R u sure?? its E?
what i think to get maximum range..we should make another mean 2300 should be taken minimum.

Sorry but why didn t you deducted from the 2300 the 115???
Thus the range is 665,000.
The answer is def not E

Thanks

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Kudos [?]: 1 [0], given: 7

Re: A house seller can deduct 5 percent from the total sales   [#permalink] 25 Nov 2012, 20:17
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