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Bunuel
A is a member of a set of numbers {2, 3, 24, 50 and 178}. If \(N= 6^A\), what is the probability that 876,463 is not a multiple of N ?

A. 0%

B. 6%

C. 40%

D. 78%

E. 100%

an be checked
N consists of only 2 and 3...
876463 is an odd number and div by 3 cant be checked by adding the digits.
so 8+7+6+4+6+3=34, NOT div by 3, so 876463 will also be not div by 3
so probability is 100%

E
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the given num 876463 is not divisible by 2 or 3. also it cant be divisible by 50 or 178.

now 6 is made up 2 and 3. so if you raise 6 to any of the numb given in the set, it will still be made of 2 and 3. hence not divisible by 6 either.

so 100%
Bunuel
A is a member of a set of numbers {2, 3, 24, 50 and 178}. If \(N= 6^A\), what is the probability that 876,463 is not a multiple of N ?

A. 0%

B. 6%

C. 40%

D. 78%

E. 100%
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