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puma
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A jogger desires to run a certain course in 1/4 less time 30 Mar 2008, 03:36
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A jogger desires to run a certain course in 1/4 less time than she usually takes. By what perceny must she increase her average running speed to accomplish this goal?

a) 20%
b) 25%
c) 33 1/3%
d) 50%
e) 75%

Tnx



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A jogger desires to run a certain course in 1/4 less time 30 Mar 2008, 03:50
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puma
A jogger desires to run a certain course in 1/4 less time than she usually takes. By what perceny must she increase her average running speed to accomplish this goal?

a) 20%
b) 25%
c) 33 1/3%
d) 50%
e) 75%

Tnx
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v1/v2 = t2/t1
v2=3/4*v1
t2/t1=4/3
So C
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puma
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A jogger desires to run a certain course in 1/4 less time 30 Mar 2008, 09:31
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The answer is correct. HOwever, I didn't get how you got it. Could you please explain.

Tnx
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sondenso
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A jogger desires to run a certain course in 1/4 less time 31 Mar 2008, 03:04
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puma
The answer is correct. HOwever, I didn't get how you got it. Could you please explain.

Tnx
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In movement problem, the speed is inversly proportional to the time of object moving.

v1 is regular speed and responding time is t1
v2 is a goal-speed and responding time is t2
t1=4, t2 is less than t1 1 unit, t2=3

v1/v2 = t2/t1 = 3/4
v2=4/3 *v1

Percent increase 33 1/3%
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A jogger desires to run a certain course in 1/4 less time 31 Mar 2008, 11:00
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Now I see. Thanks a lot for the explanation!



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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