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Bunuel
A jousting tournament requires that a team consisting of two knights and two squires. The Merry Band is forming a team from five knights and three squires. How many different lineups can The Merry Band field?

(A) 10
(B) 13
(C) 15
(D) 30
(E) 120

From 5 knights the first knight can be selected in 5 ways, next in 4 ways so, (5*4)/2=10

since we are selecting 2 item from 5 identical item we have to divide it by 2 identical

in the same manner, we have to select the squirs, so the number of squir= (3*2)/2=3

number of lineup= 10*3=30
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Bunuel
A jousting tournament requires that a team consist of two knights and two squires. The Merry Band is forming a team from five knights and three squires. How many different lineups can The Merry Band field?

(A) 10
(B) 13
(C) 15
(D) 30
(E) 120

5C2 x 3C2 = [(5 x 4) / 2] x 3 = 10 x 3 = 30

Answer: D
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Solution



Given
In this question, we are given that
    • A jousting tournament requires that a team consist of two knights and two squires.
    • The Merry Band is forming a team from five knights and three squires.

To find
We need to determine
    • The number of different lineups that Merry Band can field

Approach and Working out
In the formation of the lineup,
    • 2 knights need to be chosen from 5 knights in \(^5C_2\) or 10 ways
    • 2 squires need to be chosen from 3 squires in \(^3C_2\) or 3 ways

Hence, the number of ways the formation can be done = 10 x 3 = 30

Thus, option D is the correct answer.

Correct Answer: Option D
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