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Re: A man distributed his wealth among his wife and three sons such that [#permalink]
The answer is c. Since if we take w as wife, 1st son as a, 2nd son as b and 3rd son as c we get the total inheritance as w+a+b+c ....... (1)
We are given that
b=2a, c=2b, w=2c
If we convert these expressions in terms of b we get w=4b, c=2b and a= b/2
So substituting these values in equation (1) we get (8b+b+2b+4b)/2= 15b/2 =360° so b= 360*2/15= 48°

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A man distributed his wealth among his wife and three sons such that [#permalink]
imo c

Let eldest son got x

Second son = 2x
Youngest Son = 2(Second Son) = 4x
Wife = 2 (Youngest Son) = 8x

Total wealth of man = Wealth given to Wife + Wealth given to eldest son + Wealth given to Second son + Wealth given to Youngest Son
= 15x

Circle total angle = 360
==> Using unitary method::

15x ------------ 360

1 ------------ 360/(15x)

Second son welath = 2x, hence:
2x ------------- (360 * 2x) / 15x = 48
GMAT Club Bot
A man distributed his wealth among his wife and three sons such that [#permalink]
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