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A man's total travel expense over 3 days was \$42. What was his median

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Intern
Joined: 15 Feb 2015
Posts: 19
Location: United States
Concentration: General Management, Technology
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A man's total travel expense over 3 days was \$42. What was his median  [#permalink]

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12 Sep 2015, 11:30
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Difficulty:

55% (hard)

Question Stats:

54% (01:21) correct 46% (00:57) wrong based on 107 sessions

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A man's total travel expense over 3 days was \$42. What was his median expense?

1. On day 2, he spent \$12

2. On day 1, he spent \$14
Intern
Joined: 31 Aug 2014
Posts: 21
A man's total travel expense over 3 days was \$42. What was his median  [#permalink]

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12 Sep 2015, 14:15
3
hiteshahire22 wrote:
A man's total travel expense over 3 days was \$42. What was his median expense?

1. On day 2, he spent \$12

2. On day 1, he spent \$14

42/3 =14
SO 14 IS THE AVERAGE
ONE DAY HE SPENT 14 .. IF WE TAKE 14 IN THE MIDDLE ,THEN OTHER 1 VALUE WILL BE LESS THEN 14 .

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Re: A man's total travel expense over 3 days was \$42. What was his median  [#permalink]

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14 Sep 2015, 03:53
2
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem.
Remember equal number of variables and independent equations ensures a solution.

A man's total travel expense over 3 days was \$42. What was his median expense?

1. On day 2, he spent \$12

2. On day 1, he spent \$14

This is a typical logic questions in GMAT Math DS section. We have the average from the original condition, and the condition with the same average becomes the answer. Since the average is 42/3 = 14, and the answer for 2) is 14, B is the answer. You should definitely remember this type of DS question.

This is also a a typical type of question that relates variable approach method and common mistake type in deciding 5051.

오리지날 컨디션과 문제를 변화시키면 day 1:x, day 2:y, day 3:z라 하면 x+y+z=42일때 median=?이 되어서 미지수가 3개이고 식이 1개라서 C가 답이될 가능성이 높고 실제로 C가 답이 된다. x=14, y=12, z=16--> median=14 sufficient
그런데 이것이 key question인 통계문제여서 착각유형 4(A)를 적용하면
1)의 경우 y=12, x+z=30이 나오는데 x=12, z=18(median=12), x=15, z=15(median=15)가 되어서 unique하지 않아서 not suffi하다
2)의 경우 x=14, y+z=28에서는 y,z가 어떠한 값을 갖더라도 median=14가 나와서 unique하므로 suffi 그래서 답은 B
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Re: A man's total travel expense over 3 days was \$42. What was his median  [#permalink]

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05 May 2016, 14:35
1
Statement 1 tells us that the person spends \$12 on day 2 so remaining amount is \$30 which can be split up in \$1 and \$29 or \$15 and \$15. as we can see that median changes in both the cases So insufficient
Statement 2 tells us that the person spends \$14 on day 1 so remaining amount is \$28. Anyway we try to split the amount \$14 will remain the median. 2 cases are only possible all 3 days the spending is \$14 or one day person spends less than \$14 and the other day person spends more than \$14 so sufficient
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Re: A man's total travel expense over 3 days was \$42. What was his median  [#permalink]

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28 Dec 2017, 12:03
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Re: A man's total travel expense over 3 days was \$42. What was his median   [#permalink] 28 Dec 2017, 12:03
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