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# A manufacturer purchased three equally priced computers and ve equall

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Math Expert
Joined: 02 Sep 2009
Posts: 58396
A manufacturer purchased three equally priced computers and ve equall  [#permalink]

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21 Jan 2019, 01:27
00:00

Difficulty:

45% (medium)

Question Stats:

62% (01:08) correct 38% (00:30) wrong based on 16 sessions

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A manufacturer purchased three equally priced computers and five equally priced monitors for a total of \$4,000. If the price of each computer was 5 times the price of each monitor, how much did each computer cost?

A 200
B 400
C 600
D 800
E 1,000

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Intern
Joined: 30 Dec 2018
Posts: 34
Re: A manufacturer purchased three equally priced computers and ve equall  [#permalink]

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21 Jan 2019, 03:11
So the equation formed is 3c+ 5 M= 4000

But now we know C= 5M

So eqaution become 20M = 4000
And M is 200

So the cost of computer is 5M= 1000

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VP
Joined: 31 Oct 2013
Posts: 1467
Concentration: Accounting, Finance
GPA: 3.68
WE: Analyst (Accounting)
Re: A manufacturer purchased three equally priced computers and ve equall  [#permalink]

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21 Jan 2019, 04:09
Bunuel wrote:
A manufacturer purchased three equally priced computers and five equally priced monitors for a total of \$4,000. If the price of each computer was 5 times the price of each monitor, how much did each computer cost?

A 200
B 400
C 600
D 800
E 1,000

Total = 4000

3 equally price computers

5 equally priced monitors.

As per the question, each computer costs 5 times of each monitor.

Let each monitor costs x dollar.

Total cost of monitors = 5x.

cost of each computer = 5x

Total cost of computers = 5x *3 = 15x.

5x + 15x = 4000

20x = 4000

x = 200.

5x = 200*5 = 1000. cost of each computer.

Re: A manufacturer purchased three equally priced computers and ve equall   [#permalink] 21 Jan 2019, 04:09
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