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Bunuel
A merchant has 435 litres, 493 litres and 551 litres of three different kinds of milk. Find the least number of casks of equal size required to store all the milk without mixing.

(A) 61
(B) 51
(C) 49
(D) 47
(E) 45
Required no of casks of equal size is HCF(435, 493 & 551) = 29

So, No of casks required is \(\frac{435}{29} + \frac{493}{29} + \frac{551}{29} = 15 + 17 + 19 = 51\), Answer must be (B)
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