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# A meteorologist is attempting to calculate the average (arithmetic mea

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Math Expert
Joined: 02 Sep 2009
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A meteorologist is attempting to calculate the average (arithmetic mea  [#permalink]

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31 Jan 2019, 00:15
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100% (00:43) correct 0% (00:00) wrong based on 8 sessions

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A meteorologist is attempting to calculate the average (arithmetic mean) temperature highs for the past week. What is the arithmetic mean of the high temperatures for the last week?

(1) The mean high temperature for the past 3 days is 75 degrees. The mean high temperature for the 4 days before that was 80 degrees.

(2) The high temperatures for the last 7 days are as follows (in degrees): 80, 81, 79, 80, 77, 75, 73

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Re: A meteorologist is attempting to calculate the average (arithmetic mea  [#permalink]

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31 Jan 2019, 00:35
Statement 1: Mean of past 3 days * 3 + Mean of past 4 days * 4. Divide this by 7 to get the average for the past week.
Sufficient.

Statement 2: Gives you the temperatures for each of the individual 7 days. Just add and divide by 7.
Sufficient.

D

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Re: A meteorologist is attempting to calculate the average (arithmetic mea  [#permalink]

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31 Jan 2019, 02:42
Bunuel wrote:
A meteorologist is attempting to calculate the average (arithmetic mean) temperature highs for the past week. What is the arithmetic mean of the high temperatures for the last week?

(1) The mean high temperature for the past 3 days is 75 degrees. The mean high temperature for the 4 days before that was 80 degrees.

(2) The high temperatures for the last 7 days are as follows (in degrees): 80, 81, 79, 80, 77, 75, 73

#1
sufficient
sum of three days = 3*75 and for 4 days = 80*4
avg = 3*75+80*4/7
sufficient
#2
all data given sum/7 = avg
sufficient
IMO D
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Re: A meteorologist is attempting to calculate the average (arithmetic mea   [#permalink] 31 Jan 2019, 02:42
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