Last visit was: 06 Sep 2026, 01:27 It is currently 06 Sep 2026, 01:27
Home
Messages
Tests
Schools
Events
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
Back to Forum
Create Topic
   1   2 
805+ (Hard)|   Mixture Problems|         
User avatar
findingmyself
User avatar
Joined: 06 Apr 2025
Last visit: 05 Sep 2026
Posts: 244
Own Kudos:
179
Given Kudos: 72
Posts: 244
Kudos: 179
A milk vendor mixes water with milk and sells the mixture at the same 05 Jul 2025, 12:48
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi braddouglas10

The answer provided by Harshvardhan in this chat is the best answer and explains well. Share your specific doubts if any.

braddouglas10
Bunuel,

Since you're an incredible and competent teacher, can you please do your version of this one?
PReciSioN
Should be D, but actually both statements give different answers for X. A gives 22.72 while B gives 25. This should not happen with an official question. Right? Bunuel
Show more
User avatar
Pr4n
User avatar
Joined: 23 May 2025
Last visit: 05 Feb 2026
Posts: 92
Own Kudos:
16
Given Kudos: 42
GMAT Focus 1: 645 Q83 V82 DI80
GMAT Focus 2: 665 Q84 V85 DI80
GMAT Focus 2: 665 Q84 V85 DI80
Posts: 92
Kudos: 16
A milk vendor mixes water with milk and sells the mixture at the same 08 Jul 2025, 07:25
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Everything aside, I don't understand how is this question labeled as easy in the DI Review 2024-2025. When I looked it and wrote the equations i was already like 90s in the questions.
User avatar
k11work
User avatar
Joined: 12 Jan 2025
Last visit: 18 Nov 2025
Posts: 119
Own Kudos:
99
Given Kudos: 84
Status:Complete
Affiliations: -
-: -
Products:
My Reviews
Posts: 119
Kudos: 99
A milk vendor mixes water with milk and sells the mixture at the same 03 Aug 2025, 09:59
Kudos
Add Kudos
Bookmarks
Bookmark this Post
CapnSal
A milk vendor mixes water with milk and sells the mixture at the same price per liter as if it were undiluted milk. The selling price per liter of the mixture is the vendor’s cost per liter of the milk plus a markup of x %. The water costs the vendor nothing. If the vendor gets a 50% profit on the sale of the mixture, what is the value of x ?

(1) If the vendor mixes half the intended quantity of water and sells every liter of the mixture at the cost price per liter of the undiluted milk, the vendor will get a 10% profit.

(2) The concentration of milk in the mixture after adding water is 5/6.­


ID: 700325

Show Spoiler
Unable to add tags but this is from Official Online Question Bank for DI Review 2024-25­
­
Show more

Points to Note :
Mixture(M) sold at same price as milk(m)
CP=CP of milk
SP=CP(1+x/100)
P=50%
SP-CP=0.5CP
SP=1.5CP
CP(1+x/100)M=1.5CP*m
m/M=1+x/100 ...... (i)
x = ?

Statement 1
So,
SP=1.1CP
M=2m
CP(1+x/100)2m=1.1CP*m
(1+x/100)2 = 1.1
We can find x from here.
SUFFICIENT.

Statement 2
m=5/6M
If we substitute this in i, we can get x.
SUFFICIENT.

Ans D
User avatar
rockstar09rulez
User avatar
Joined: 30 Sep 2023
Last visit: 26 Aug 2026
Posts: 43
Own Kudos:
25
Given Kudos: 74
Location: United States (CA)
Concentration: Technology, Finance
Products:
GMAT Club Tests
Posts: 43
Kudos: 25
A milk vendor mixes water with milk and sells the mixture at the same 20 Jun 2026, 16:12
Kudos
Add Kudos
Bookmarks
Bookmark this Post
SP per liter of mix = CP per liter of milk + x% mkup (Notice per liter here) -----> (1)

Entire mixture (milk + water) is sold at the price of the milk (assuming water is also milk) - There is a 50% profit on the sale of Mixture

Let's assume we started with 100 liters of milk and CP per liter of milk is $1

Stmt 1: If the vendor mixes half the intended quantity of water and sells every liter of the mixture at the cost price per liter of the undiluted milk, the vendor will get a 10%
profit.

Let water be y liters
100 liters + y/2 water sold at the cost per liter of milk (no water) gives 10% profit. Since water has no cost, CP of mix = $100, SP of mix = $110 (10 liters of water added)
100 liters + y water sold at the cost per liter of milk (no water) gives 20% profit. Since water has no cost, CP of mix = $100, SP of mix = $120 (20 liters of water added)

Now actual SP of mix with markup is $150
SP of 120 liters of mix is $150
SP of 1 liter of mix = (150/120) = $1.25
Now go to equation 1:
SP per liter of mix = CP per liter of milk + x% mkup
$1.25 = $1 + $0.25
$0.25 markup on $1 means a 25% markup . So, x = 25% --> SUFFICIENT

Stmt 2: The concentration of milk in the mixture after adding water is 5/6.
Again assuming 100 liters of milk, w liters of water
100/(100 + w) = 5/6, gives w = 20 liters, same as what we got in statement 1. So, by same calculation as statement 1, x = 25%. --> SUFFICIENT

Hence, D is the answer. Each statement alone is sufficient.
   1   2 
Moderators:
Bunuel
Math Expert
113157 posts
FrozenDragon
DI Forum Moderator
409 posts