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A number 15B is divisible by 6. Which of these will be true about the positive integer B?
(A) B will be even
(B) B will be Odd
(C) B will be divisible by 6
(D) Both a & b
(E) A, B and C
Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
(A) B will be even
(B) B will be Odd
(C) B will be divisible by 6
(D) Both a & b
(E) A, B and C
Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
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02 Jun 2025, 00:38
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If 15B is divisible by 6, then the number is even. This eliminates option B,D and E
For 15B to be divisible by 3, 6+B should be divisible by 3. Only options for B are 0 and 6 as B needs to be even. Both these are divisible by 6
Both A and C will be true about the positive integer B
It seems option D should read Both a and c
For 15B to be divisible by 3, 6+B should be divisible by 3. Only options for B are 0 and 6 as B needs to be even. Both these are divisible by 6
Both A and C will be true about the positive integer B
It seems option D should read Both a and c
Bunuel
02 Jun 2025, 07:03
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Bunuel
Given that 15B is divisible by 6.
To be divisible by 6, the number has to be ➗ divided by both 2 and 3.
Digit B has to be even number. So digits B can be { 0,2,4,6,8}.
For divisibility of 3, the sum of digits has to be divisible by ➗ 3. 1+5+B = 6+B is divided by 3.
Possible cases :
6+0 = 6
6+3 = 9
6+6 = 12
6+9 = 15
So, B can be { 0, 3,6,9}.
Overlapping values are 0 and 6.
(A) B will be even ✅
(B) B will be Odd
(C) B will be divisible by 6 ✅
(D) Both a & b
(E) A, B and C.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
