Bunuel
A number of apples and oranges are to be distributed evenly among a number of baskets. Each basket will contain at least one of each type of fruit. If there are 20 oranges to be distributed, what is the minimum number of apples needed so that every basket contains less than twice as many apples as oranges?
(1) If the number of baskets were halved and all other conditions remained the same, there would be twice as many oranges in every remaining basket.
(2) If the number of oranges were halved, it would no longer be possible to place an orange in every basket.
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https://gmatclub.com/forum/a-number-of- ... 99963.htmlQuestion: what is the minimum number of apples needed so that every basket contains less than twice as many apples as oranges?
If Ap is the number of apples and Or is the number of oranges, Ap < 2*Or.
Since we need the minimum number of apples, this given inequality is pointless anyway.
Number of baskets would be a factor of 20.
(1) If the number of baskets were halved and all other conditions remained the same, there would be twice as many oranges in every remaining basket.
Tells us that number of baskets is even. Oranges can be distributed when we halve the number of baskets. Rest, it tells us nothing else. This is obvious data.
If I have 20 oranges and 10 baskets, I give 2 oranges to each basket.
If I have 20 oranges and 5 baskets (half), I give 4 oranges (twice) to each basket.
So what it tells us is basic mathematics. The only info is that number of baskets is not odd such as 5.
Number of baskets could be 10 or 20 (etc.) and minimum number of apples needed in those two cases would be 10 and 20 respectively. Not sufficient.
(2) If the number of oranges were halved, it would no longer be possible to place an orange in every basket.
If there were 10 oranges, there wouldn't be 1 orange for each basket. So number of baskets is greater than 10. So there must have been 20 baskets, the only factor of 20 that is greater than 10. Hence we need minimum 20 apples.
Sufficient
Answer (B)