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A number of marbles were divided between Amy and Betty such that the

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A number of marbles were divided between Amy and Betty such that the  [#permalink]

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New post 25 Sep 2018, 05:13
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74% (01:27) correct 26% (01:39) wrong based on 19 sessions

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A number of marbles were divided between Amy and Betty such that the ratio of Amy’s marbles to Betty’s marbles was 5:3. If Amy’s marbles exceeded (5/9)th of the total marbles by $100, how many marbles Betty has?

(A) $420
(B) $540
(C) $640
(D) $750
(E) $900

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Re: A number of marbles were divided between Amy and Betty such that the  [#permalink]

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New post 25 Sep 2018, 05:21
Bunuel wrote:
A number of marbles were divided between Amy and Betty such that the ratio of Amy’s marbles to Betty’s marbles was 5:3. If Amy’s marbles exceeded (5/9)th of the total marbles by $100, how many marbles Betty has?

(A) $420
(B) $540
(C) $640
(D) $750
(E) $900



Ratio of Marbles: 5 : 3

Let Amy has 5x marbles and betty has 3x marbles.

Total marbles = 8x.

Can form equation :

5x = 8x (5/9) +100

5x - 40x /9 = 100

5x = 900

x = 180.

Betty's Marbles = 180 * 3 = 540


The best answer is B.
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Re: A number of marbles were divided between Amy and Betty such that the &nbs [#permalink] 25 Sep 2018, 05:21
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A number of marbles were divided between Amy and Betty such that the

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