Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Jul 1011:00 AM PDT
-11:00 AM PDT
In our conversation, Kishore talks about how strategically he used data analytics to identify high impact areas to focus on as well as his early morning study routine (3 AM prep!) that optimized his GMAT preparation.- Jun 30
08:00 AM PDT
-11:59 PM PDT
Join us June 30th for 2 weeks of GMAT questions (just 8 per day) to help with your prep and to compete with your fellow GMAT Clubbers for a chance to win a prize fund of $30,000 for you and your team-mates! 
Jul 0901:00 PM EDT
-02:00 PM EDT
More Target Test Prep students are earning 100th percentile GMAT scores. Don’t settle for less when the Target Test Prep course gives you everything you need to score high on the GMAT. Start your 5-day free trial today.
Jul 1206:30 AM PDT
-08:30 AM PDT
Join our webinar to master GMAT RC Main Point Questions! Learn effective strategies to decipher passage themes and purposes. Senior Verbal Expert- Sunita Singhvi will equip you with tools to navigate complexities and avoid common traps set by the GMAT.
Jul 1211:00 AM IST
-01:00 PM IST
Attend this session to learn how to Deconstruct arguments, Pre-Think Author’s Assumptions, and apply Negation Test.
Jul 1311:00 AM EDT
-12:30 PM EDT
Looking for your GMAT motivation to break through the score plateau? Pragati improved her score by massive 160 points with strategic guidance and hard-work! Find out how personalized mentorship and a strong mindset can turn GMAT struggles into success.
Jul 1508:00 PM PDT
-09:00 PM PDT
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Jul 1611:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
06 Jan 2021, 06:32
Kudos
Bookmarks
A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
91% (01:28) correct
9%
(01:32)
wrong
based on 87
sessions
History
Date
Time
Result
Not Attempted Yet
A parking garage has spaces for cars and vans only. If there is a total of 118 vehicles in the garage, how many of them are vans?
(1) If 14 more vans are driven into the garage, there will be twice as many vans as cars in the garage.
(2) If x vans and y cars are driven into the garage, there will be an equal number of vans and cars in the garage.
(1) If 14 more vans are driven into the garage, there will be twice as many vans as cars in the garage.
(2) If x vans and y cars are driven into the garage, there will be an equal number of vans and cars in the garage.
06 Jan 2021, 07:01
Kudos
Bookmarks
Bunuel
A parking garage has spaces for cars and vans only. If there is a total of 118 vehicles in the garage, how many of them are vans?
(1) If 14 more vans are driven into the garage, there will be twice as many vans as cars in the garage.
(2) If x vans and y cars are driven into the garage, there will be an equal number of vans and cars in the garage.
(1) If 14 more vans are driven into the garage, there will be twice as many vans as cars in the garage.
(2) If x vans and y cars are driven into the garage, there will be an equal number of vans and cars in the garage.
Given: A parking garage has spaces for cars and vans only. There is a total of 118 vehicles in the garage,
Let C = the number of cars
Let V = the number of vans
We can write: C + V = 118
Target question: What is the value of V?
Statement 1: If 14 more vans are driven into the garage, there will be twice as many vans as cars in the garage
We can write: V + 14 = 2C
We now have the following system of two different linear equations:
V + 14 = 2C
C + V = 118
Since we COULD solve the system for C and for V, we could answer the target question (although we would never waste valuable time on test day doing so)
Statement 1 is NOT SUFFICIENT
Statement 2: If x vans and y cars are driven into the garage, there will be an equal number of vans and cars in the garage.
We can write: V + x = C + y
There are several values of x, y, V and C that satisfy statement 2 (and the given information, C + V = 118). Here are two possible cases:
Case a: V = 59, C = 59, x = 3 and y = 3. In this case, the answer to the target question is V = 59
Case b: V = 58, C = 60, x = 3 and y = 1. In this case, the answer to the target question is V = 58
Since we can’t answer the target question with certainty, statement 2 is NOT SUFFICIENT
Answer: A
Cheers,
Brent
noobieTopro
06 Jan 2021, 07:12
Kudos
Bookmarks
Bunuel
A parking garage has spaces for cars and vans only. If there is a total of 118 vehicles in the garage, how many of them are vans?
(1) If 14 more vans are driven into the garage, there will be twice as many vans as cars in the garage.
(2) If x vans and y cars are driven into the garage, there will be an equal number of vans and cars in the garage.
(1) If 14 more vans are driven into the garage, there will be twice as many vans as cars in the garage.
(2) If x vans and y cars are driven into the garage, there will be an equal number of vans and cars in the garage.
Let Vans = V and Cars = C
C+V =118
(1) If 14 more vans are driven into the garage, there will be twice as many vans as cars in the garage.
V+14 = 2C
2C - V = 14
Now we have 2 equations.
Therefore, we can get C=44, V=74
Therefore, statement (1) alone is sufficient.
(2) If x vans and y cars are driven into the garage, there will be an equal number of vans and cars in the garage.
C+y = V+x
Now, here we have 2 additional variable.
Therefore, we wont be able to get a definite answer on substitution.
Therefore, statement (2) alone is insufficient.
Answer is A.
