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Difficulty:
35%
(medium)
Question Stats:
71% (01:57) correct
29%
(01:44)
wrong
based on 155
sessions
History
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A payroll record with an error in it is placed in a filing cabinet with six error-free payroll records. Two payroll records are randomly selected, without replacement, by an auditor. What is the probability of drawing a corrupted payroll record on the first or the second draw?
A. 1/42
B. 1/21
C. 2/21
D. 1/7
E. 2/7
A. 1/42
B. 1/21
C. 2/21
D. 1/7
E. 2/7
\({P}_{(\text{No Error in both draw})} = \dfrac{6}{7} \times \dfrac{5}{6} = \dfrac{30}{42}\)
\(P_{(\text{Error})} = 1 - \dfrac{30}{42} = \dfrac{12}{42} = \dfrac{2}{7}\)
Ans E
\(P_{(\text{Error})} = 1 - \dfrac{30}{42} = \dfrac{12}{42} = \dfrac{2}{7}\)
Ans E
