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Bunuel
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Bunuel I was actually calculating the fact that:
Both accept + Both reject = 50 (since 82 went into C)
Now I also know 32 were rejected by C alone so the total count to the above equation is added by 32

50+32 = Both accept + Both reject = 82

So now I know the summation has to be 82.

Now I knew it has to be a combination of 37 and 45 only and ended up choosing the other way and yeah the method is very efficient that you mentioned but in my solution how can i quickly prove if Rejection>Both accept or the other way? Because that is all I would need to find out the answer in this case. Or would I have to work out Both properly and work it out?
I just wanna know if I could deduce the inequality from my equation somehow which im unable to

Thankyou!
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A candidate applying for a research program must undergo up to three interview cycles. The first interview is conducted by A, followed by B, and, if necessary, by C. A candidate is selected as soon as exactly two interviewers provide a recommendation. For example, if both A and B recommend a candidate, the candidate is selected and does not proceed to an interview with C. C interviews only those candidates recommended by exactly one of A or B.

A total of 132 candidates applied for the research program, of which C interviewed 82. The number of candidates recommended by A, B, and C were 70, 86, and 50, respectively.

Based on the information provided, select for Both A and B the number of candidates recommended by both A and B, and select for Rejected the total number of candidates out of 132 who were not selected for the research program.
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Unfortunately, no. Your equation alone doesn't contain enough information to determine the split. Here's why:

Your equation tells you: x + Rejected = 82

But this has multiple solutions (37+45 or 45+37). To break the tie, you must use the given recommendation numbers.

Quick calculation to find "Both A and B":

We know:
- A recommended = 70
- B recommended = 86
- C interviewed = 82 (exactly one of A or B)

Add A's and B's totals: 70 + 86 = 156

This counts "Both A and B" twice (once in A's count, once in B's count).
The rest (exactly one of A or B) is counted once = 82

So: 2x + 82 = 156
x = 37

Therefore: Both A and B = 37, Rejected = 82 - 37 = 45

Adit_
Bunuel I was actually calculating the fact that:
Both accept + Both reject = 50 (since 82 went into C)
Now I also know 32 were rejected by C alone so the total count to the above equation is added by 32

50+32 = Both accept + Both reject = 82

So now I know the summation has to be 82.

Now I knew it has to be a combination of 37 and 45 only and ended up choosing the other way and yeah the method is very efficient that you mentioned but in my solution how can i quickly prove if Rejection>Both accept or the other way? Because that is all I would need to find out the answer in this case. Or would I have to work out Both properly and work it out?
I just wanna know if I could deduce the inequality from my equation somehow which im unable to

Thankyou!

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