1. There are 6 different scenarios or groups for each person:
- Group 1: were not recommended by both A and B, therefore not even going to C.
- Group 2: were recommended by A, not by B, therefore going to C and not getting recommended.
- Group 3: were recommended by A, not by B, therefore going to C and getting recommended.
- Group 4: were recommended by A and B, therefore going to C.
- Group 5: were not recommended by A, recommended by B, therefore going to C and not getting recommended.
- Group 6: were not recommended by A, recommended by B, therefore going to C and getting recommended.
2. Let each group have a number of people G1, G2, G3,.... Then, we can build the following table:
Groups | A | B | C |
1 | 0 | 0 | Not interviewed (0) |
2 | G2 | 0 | 0 |
3 | G3 | 0 | G3 |
4 | G4 | G4 | Not interviewed (0) |
5 | 0 | G5 | 0 |
6 | 0 | G6 | G6 |
# of recommended | 70 | 86 | 50 |
3. Based on the given information, the following two equations can be said:
- (1): G1 + G2 + G3 + G4 + G5 + G6 = 132
- (2): G2 + G3 + G5 + G6 = 82
4. The question asks us to find G4 and the sum G1 + G2 + G5.
5. From the table, we can add the two equations: G2 + G3 + G4 = 70, G4 + G5 + G6 = 86 \(\rightarrow\) G2 + G3 + G4 + G5 + G6 + G4 = 156 = G1 + G2 + G3 + G4 + G5 + G6 - G1 + G4 = 132 - G1 + G4 \(\rightarrow\) G4 - G1 = 24.
6. Using (2) and (1), 82 = G2 + G3 + G5 + G6 = (G1 + G2 + G3 + G4 + G5 + G6) - (G1 + G4) = 132 - (G1 + G4) \(\rightarrow\) G1 + G4 = 132 - 82 = 50.
7. Let's add the two resulting equations: (G4 - G1) + (G1 + G4) = (24) + (50) \(\rightarrow 2 *\)G4 = 74 \(\rightarrow\)
G4 = 37. Also, G1 = 37 - 24 = 13.
8. Using equation (2) and that G3 + G6 = 50, it can be said that: 82 = G2 + G3 + G5 + G6 = 50 + G2 + G5 \(\rightarrow\) G2 + G5 = 32.
9. That means
G1 + G2 + G5 = 13 + 32 =
45.
10. Our answer will be:
Both A and B - 37 and Rejected - 45.