It is currently 23 Mar 2018, 22:51

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# A person borrowed a certain sum at the rate of 20% per annum

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:

### Hide Tags

Intern
Joined: 01 Dec 2012
Posts: 38
Location: India
WE: Project Management (Retail)
The median of the series sin[m]1^{ [#permalink]

### Show Tags

31 Jan 2013, 07:27
Q1. The median of the series sin$$1^{\circ}$$, sin$$2^{\circ}$$, sin$$3^{\circ}$$,...............,sin$$179^{\circ}$$ is

a. 1
b. $$1/\sqrt{2}$$
c. sin$$46^{\circ}$$
d. sin$$89^{\circ}$$
e. sin$$98^{\circ}$$

Q2. If the Standard deviation of 1,2,3,4,5,6,7,8,9,10,11 is M, then the standard deviation of 101,102,103,...................,111 is
a. M
b. 100+M
c. 100-M
d. M-100
e. 100M

1.
[Reveal] Spoiler:
b

2.
[Reveal] Spoiler:
a
Senior Manager
Joined: 28 Apr 2012
Posts: 304
Location: India
Concentration: Finance, Technology
GMAT 1: 650 Q48 V31
GMAT 2: 770 Q50 V47
WE: Information Technology (Computer Software)
Re: The median of the series sin[m]1^{ [#permalink]

### Show Tags

31 Jan 2013, 07:42
Q1. The median of the series sin$$1^{\circ}$$, sin$$2^{\circ}$$, sin$$3^{\circ}$$,...............,sin$$179^{\circ}$$ is

a. 1
b. $$1/\sqrt{2}$$
c. sin$$46^{\circ}$$
d. sin$$89^{\circ}$$
e. sin$$98^{\circ}$$

Is this a GMAT question ?

Ans: B

sin function starts from sin$$0^{\circ}$$ = 0 increases till sin$$90^{\circ}$$ = 1 , then decreases till sin$$180^{\circ}$$ = 0
and sin$$x^{\circ}$$ = sin$$(180 - x)^{\circ}$$

So the mid value occurs at sin$$45^{\circ}$$ or sin$$135^{\circ}$$ = $$1/\sqrt{2}$$

Q2. If the Standard deviation of 1,2,3,4,5,6,7,8,9,10,11 is M, then the standard deviation of 101,102,103,...................,111 is
a. M
b. 100+M
c. 100-M
d. M-100
e. 100M

Ans: A

Theory: The standard deviation remains unchanged if we add a constant to every term.
_________________

"Appreciation is a wonderful thing. It makes what is excellent in others belong to us as well."
― Voltaire

Press Kudos, if I have helped.
Thanks!

Math Expert
Joined: 02 Sep 2009
Posts: 44419
Re: A person borrowed a certain sum at the rate of 20% per annum [#permalink]

### Show Tags

04 Jan 2018, 02:54
Bump.......................................
_________________
Re: A person borrowed a certain sum at the rate of 20% per annum   [#permalink] 04 Jan 2018, 02:54

Go to page   Previous    1   2   3   [ 43 posts ]

Display posts from previous: Sort by

# A person borrowed a certain sum at the rate of 20% per annum

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.