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27 Nov 2024, 01:30
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Difficulty:
55%
(hard)
Question Stats:
59% (02:00) correct
41%
(02:00)
wrong
based on 154
sessions
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A planed named "ship" is flying in a clock wise circular path above Town X. A plane named "car" is also flying in a clockwise circular path above town X at a different altitude and speed from Plane named ship. if the circumference of the path of plane Ship is equal to the circumference of the path of plane Car, and at 5pm are directly above the same location over town X, how many circular paths must the planes make so that both planes are directly above the same location at the same time above Town X.
(1) The circumference of the circular path traveled by both planes is 4 pi miles ( pi = 3.14)
(2) The plane ship travels at a constant rate of \(\frac{1}{8}\) of the length of circular path per hour, and plane car travels at a constant rate of \(\frac{1}{6}\) of the length of circular path per hour.
(1) The circumference of the circular path traveled by both planes is 4 pi miles ( pi = 3.14)
(2) The plane ship travels at a constant rate of \(\frac{1}{8}\) of the length of circular path per hour, and plane car travels at a constant rate of \(\frac{1}{6}\) of the length of circular path per hour.
10 Dec 2024, 00:40
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OptionA
I know 2xpixr = 4xpi -> R = 2. But speed is different. Insufficient.
Option B
Time for total rotation is 6 hrs and 8 hrs respectively. We can take the LCM i.e. 24 hours for meeting again.
Total Number of circular paths = 24/6 + 24/8 = 4 + 3 = 7
Sufficient
Official Explanation please?
I know 2xpixr = 4xpi -> R = 2. But speed is different. Insufficient.
Option B
Time for total rotation is 6 hrs and 8 hrs respectively. We can take the LCM i.e. 24 hours for meeting again.
Total Number of circular paths = 24/6 + 24/8 = 4 + 3 = 7
Sufficient
Official Explanation please?
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