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28 Sep 2007, 05:23
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A professional gambler has won 40% of his 25 poker games for the week so far. If all of a sudden, his luck changes and he begins winning 80% of the time, how many more games must he play to end up winning 60% of all his games for the week?
I'm little confused by this question. The first part says he played 25 games for the week and he won 40% so he won 10 games. I don't understand the second line and how it will fit to give me an answer. When it says 80% of time, what does that mean? What does that 80% of time relate to next week, next two weeks, next month ??????
Can someone please clarify with answer?
I'm little confused by this question. The first part says he played 25 games for the week and he won 40% so he won 10 games. I don't understand the second line and how it will fit to give me an answer. When it says 80% of time, what does that mean? What does that 80% of time relate to next week, next two weeks, next month ??????
Can someone please clarify with answer?
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28 Sep 2007, 05:41
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40% means that for every 2 games he wins he lose 3.
80% means that for every 4 games he wins he lose 1.
after 25 games at 40% ---> won 10 and lost 15
after x more games at 80% ---> won (x/5)*4 and lost x/5
so in order to get 60% total winning:
(10+(x/5)*4)/(25+x) = 3/5
(10+4x/5)/(25+x) = 3/5
5*(10+4x/5) = 75+x
50+4x = 75+x
x = 25
x = 50 ---> he has to play 50 games.
first 25 games ---> win 10 lose 15 ---> 10/25 = 40%
then 25 games ---> win 20 lose 5 ---> 20/25 = 80%
total 50 games ---> win 30 lose 20 ---> 30/50 = 60%
80% means that for every 4 games he wins he lose 1.
after 25 games at 40% ---> won 10 and lost 15
after x more games at 80% ---> won (x/5)*4 and lost x/5
so in order to get 60% total winning:
(10+(x/5)*4)/(25+x) = 3/5
(10+4x/5)/(25+x) = 3/5
5*(10+4x/5) = 75+x
50+4x = 75+x
x = 25
x = 50 ---> he has to play 50 games.
first 25 games ---> win 10 lose 15 ---> 10/25 = 40%
then 25 games ---> win 20 lose 5 ---> 20/25 = 80%
total 50 games ---> win 30 lose 20 ---> 30/50 = 60%
