aparnaharish wrote:

A Prototype fuel-efficient car (P-Car) is estimated to get 80% more miles per gallon of gasoline

than does a traditional fuel-efficient car (T-Car). However, the P-Car requires a special type

of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car. If the two

cars are driven the same distance, what percent less than the money spent on gasoline for the

T-Car is the money spent on gasoline for the P-Car?

A) 16 2/3%

B) 33 1/3 %

C) 50%

D) 60%

E) 66 2/3 %

let say T car travel 100 miles with 100 $ gasoline

therefore according to quest

P car will travell 180(80%more) mile and gasoline cost will be 120(20%more)

therfore p car will travel \(100\) miles in \((120/180)*100\) $= \(200/3\) $

difference of money for both cars travelling for 100 miles = 100-(200/3) = 100/3

so percentage less will be ((100/3)/100)*100 (DENOMINATOR IS 100 as cost for T was 100 $...and multiplying by 100 in order to take out the percent value)

= 33 1/3

hence B

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