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A radio station has to choose three days of the seven

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A radio station has to choose three days of the seven [#permalink]

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New post 03 Dec 2012, 12:02
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  5% (low)

Question Stats:

91% (00:51) correct 9% (01:11) wrong based on 113 sessions

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A radio station has to choose three days of the seven in a week to broadcast a certain program, and that set will repeat each week. The program can be broadcast equally on any of the seven weekdays —- weekdays vs. weekends don’t matter at all —- nor does it matter whether the days the program airs are adjacent or not. Absolutely any three of the seven weekdays can be chosen. How many different three-day combinations of the seven weekdays can be constructed?
(A) 9
(B) 15
(C) 21
(D) 35
(E) 56


For tips on calculating the answer to questions like this without a calculator, see this post:
http://magoosh.com/gmat/2012/gmat-math- ... binations/
Experts, feel free to share you own non-calculator tips for calculating nCr values.

Mike :-)
[Reveal] Spoiler: OA

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Mike McGarry
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Kudos [?]: 8731 [1], given: 105

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Re: A radio station has to choose three days of the seven [#permalink]

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New post 04 Dec 2012, 00:59
mikemcgarry wrote:
A radio station has to choose three days of the seven in a week to broadcast a certain program, and that set will repeat each week. The program can be broadcast equally on any of the seven weekdays —- weekdays vs. weekends don’t matter at all —- nor does it matter whether the days the program airs are adjacent or not. Absolutely any three of the seven weekdays can be chosen. How many different three-day combinations of the seven weekdays can be constructed?
(A) 9
(B) 15
(C) 21
(D) 35
(E) 56


For tips on calculating the answer to questions like this without a calculator, see this post:
http://magoosh.com/gmat/2012/gmat-math- ... binations/
Experts, feel free to share you own non-calculator tips for calculating nCr values.

Mike :-)


Pick 3 days out of 7.. 7C3 = 7!/(4!*3!) = 35

Ans D it is.
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Re: A radio station has to choose three days of the seven [#permalink]

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New post 27 Dec 2012, 02:38
I used the ANAGRAM technique to answer this question:

D1 D2 D3 D4 D5 D6 D7
N N N Y Y Y N


ANAGRAM gets the permutation of the options and then divide it by the number of selected and the number of not selected. In our case, we are looking for the permutation of 7 days divided by 3 selections and 4 non-selections.

\(=\frac{7!}{4!3!}=7*5=35\)

Answer: D
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Re: A radio station has to choose three days of the seven [#permalink]

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New post 04 Mar 2015, 04:11
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: A radio station has to choose three days of the seven [#permalink]

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New post 21 Oct 2016, 03:49
Lots of statements and words to confuse a test - taker
basically the question is asking to select 3 days from seven days of the week
7 C 3 = \(\frac{7!}{(7-3)!3!}\) = 35

Correct answer - D

Kudos [?]: 40 [0], given: 231

Re: A radio station has to choose three days of the seven   [#permalink] 21 Oct 2016, 03:49
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