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A rectangle is defined to be "silver" if and only if the ratio of its length to its width is 2 to 1. If rectangle S is silver, is rectangle R silver?
(1) R has the same area as S
(2) The ratio of one side of R to one side of S is 2 to 1.
(1) R has the same area as S
(2) The ratio of one side of R to one side of S is 2 to 1.
Solving this question helps.
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17 Oct 2013, 23:56
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TGC
Consider two cases:
S is 4 by 2 and R is 4 by 2.
S is 4 by 2 and R is 8 by 1.
Answer: E.
Hope it helps.
General Discussion
17 Oct 2013, 22:38
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Since "S" is silver the ratio for its L/B=2/1
(1).
Sides of R can be in any ratio provided the area of R=S
Consider for S : 4:2
For R it can be : 4:2 or 8:1
Hence Insufficient
(2).
Consider this we don't have enough info
Hence Insufficient
Combining them
Consider length of R/S=2/1 and both the areas will have to be same
S: L=2 and B=1
R: L=4 and B=1/2 Hence R is not silver
Consider width of R/S = 2/1 and both the areas will have to be same
S: L=4 and B=2
R: L=2 and B=4 Hence R is not silver
Hence Both combined are sufficient. However , per the source the answer is (E).
Please advise what I am missing here.
Rgds,
TGC!
(1).
Sides of R can be in any ratio provided the area of R=S
Consider for S : 4:2
For R it can be : 4:2 or 8:1
Hence Insufficient
(2).
Consider this we don't have enough info
Hence Insufficient
Combining them
Consider length of R/S=2/1 and both the areas will have to be same
S: L=2 and B=1
R: L=4 and B=1/2 Hence R is not silver
Consider width of R/S = 2/1 and both the areas will have to be same
S: L=4 and B=2
R: L=2 and B=4 Hence R is not silver
Hence Both combined are sufficient. However , per the source the answer is (E).
Please advise what I am missing here.
Rgds,
TGC!
