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Re: A rectangle is defined to be "silver" if and only if the rat [#permalink]
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Because they are both rectangles, does it matter that we don't know the side which the ratio is applied to from (2)? In other words, is the test trying to trick us by specifying that "if and only if the ratio of its length to its width is 2 to 1" whereas (2) doesn't specify if the ratio is of length to width or width to length?
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Re: A rectangle is defined to be "silver" if and only if the rat [#permalink]
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WholeLottaLove
Because they are both rectangles, does it matter that we don't know the side which the ratio is applied to from (2)? In other words, is the test trying to trick us by specifying that "if and only if the ratio of its length to its width is 2 to 1" whereas (2) doesn't specify if the ratio is of length to width or width to length?

(2) is not sufficient, because it talks about R and S, not only about R: The ratio of one side of R to one side of S is 2 to 1.
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Re: A rectangle is defined to be "silver" if and only if the rat [#permalink]
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WholeLottaLove
Because they are both rectangles, does it matter that we don't know the side which the ratio is applied to from (2)? In other words, is the test trying to trick us by specifying that "if and only if the ratio of its length to its width is 2 to 1" whereas (2) doesn't specify if the ratio is of length to width or width to length?

(2) is not sufficient, because it talks about R and S, not only about R: The ratio of one side of R to one side of S is 2 to 1.

Does my attached diagram make sense?
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Re: A rectangle is defined to be "silver" if and only if the rat [#permalink]
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TGC
A rectangle is defined to be "silver" if and only if the ratio of its length to its width is 2 to 1. If rectangle S is silver, is rectangle R silver?

(1) R has the same area as S
(2) The ratio of one side of R to one side of S is 2 to 1.

The correct answer is (E) , as proved in the ALGEBRAIC-GEOMETRIC BIFURCATION shown in the image attached.


This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
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Re: A rectangle is defined to be "silver" if and only if the rat [#permalink]
S is 2x by x so that it's a "silver"

(1) Area of R is 2x^2
R can be 2x by x so that it's a "sliver"
or 2/3x by 3x so it's not a sliver
Insufficient

(2) R can be 4x by 100000x
Or 4x by 2x
ETC.
Insufficient

(1) and (2)
R is 4x by 1/2x which is not a sliver
Or 2x by x which is a sliver

Answer E
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Re: A rectangle is defined to be "silver" if and only if the rat [#permalink]
gmatophobia

A rectangle is defined to be "silver" if and only if the ratio of its length to its width is 2 to 1. If rectangle S is silver, is rectangle R silver?

(1) R has the same area as S
(2) The ratio of one side of R to one side of S is 2 to 1.



Let say side of S is 2cm, 4cm

Combining I and II, one of the side of R will be either 4cm or 8cm
Area of S is 8cm, now since area is same then, then sides of R will be 4cm*2cm or 8cm*1cm
Thus since we are getting two cases where one satisfies and other doesn't answer will be option E

Is this logic correct?
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Re: A rectangle is defined to be "silver" if and only if the rat [#permalink]
Rickooreo
gmatophobia

A rectangle is defined to be "silver" if and only if the ratio of its length to its width is 2 to 1. If rectangle S is silver, is rectangle R silver?

(1) R has the same area as S
(2) The ratio of one side of R to one side of S is 2 to 1.



Let say side of S is 2cm, 4cm

Combining I and II, one of the side of R will be either 4cm or 8cm
Area of S is 8cm, now since area is same then, then sides of R will be 4cm*2cm or 8cm*1cm
Thus since we are getting two cases where one satisfies and other doesn't answer will be option E

Is this logic correct?

This logic is correct !
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Re: A rectangle is defined to be "silver" if and only if the rat [#permalink]
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Re: A rectangle is defined to be "silver" if and only if the rat [#permalink]
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