GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 14 Dec 2019, 22:23

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# A rectangle with diagonal length x is twice as long as it is wide. Wha

Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 59725
A rectangle with diagonal length x is twice as long as it is wide. Wha  [#permalink]

### Show Tags

22 Mar 2019, 00:52
00:00

Difficulty:

65% (hard)

Question Stats:

58% (02:02) correct 42% (01:56) wrong based on 45 sessions

### HideShow timer Statistics

A rectangle with diagonal length x is twice as long as it is wide. What is the area of the rectangle?

(A) x^2/4
(B) 2x^2/5
(C) x^2/2
(D) x^2
(E) 3x^2/2

_________________
GMAT Club Legend
Joined: 18 Aug 2017
Posts: 5483
Location: India
Concentration: Sustainability, Marketing
GPA: 4
WE: Marketing (Energy and Utilities)
Re: A rectangle with diagonal length x is twice as long as it is wide. Wha  [#permalink]

### Show Tags

22 Mar 2019, 04:01
Bunuel wrote:
A rectangle with diagonal length x is twice as long as it is wide. What is the area of the rectangle?

(A) x^2/4
(B) 2x^2/5
(C) x^2/2
(D) x^2
(E) 3x^2/2

l= 2y
width = y
d=x
so area = 2y^2
and digonal = √4y^2+y^2
x= √5y^2= y√5
y= x/√5
so
area= 2*y^2

2*x^2/5
IMO B
Intern
Joined: 02 Sep 2018
Posts: 27
Schools: Stanford MSx '21
Re: A rectangle with diagonal length x is twice as long as it is wide. Wha  [#permalink]

### Show Tags

22 Mar 2019, 08:42
1
Let width be y, hence length = 2y
Accordingly area = 2y^2

From the diagonal x, we get the relationship using y^2+4y^2 = x^2
Hence y^2=x^2/5
Area = 2*x^2/5
Ans B
Intern
Joined: 08 Dec 2018
Posts: 11
Location: India
Schools: ISB '20, IIMA PGPX"20
Re: A rectangle with diagonal length x is twice as long as it is wide. Wha  [#permalink]

### Show Tags

24 Mar 2019, 07:33
1
Bunuel wrote:
A rectangle with diagonal length x is twice as long as it is wide. What is the area of the rectangle?

(A) x^2/4
(B) 2x^2/5
(C) x^2/2
(D) x^2
(E) 3x^2/2

The language of this question indicates that length of the diagonal is twice the breadth. How you assumed that the length is twice the breadth?
Am I missing something, please clarify?
Target Test Prep Representative
Status: Founder & CEO
Affiliations: Target Test Prep
Joined: 14 Oct 2015
Posts: 8701
Location: United States (CA)
Re: A rectangle with diagonal length x is twice as long as it is wide. Wha  [#permalink]

### Show Tags

24 Mar 2019, 18:43
1
Bunuel wrote:
A rectangle with diagonal length x is twice as long as it is wide. What is the area of the rectangle?

(A) x^2/4
(B) 2x^2/5
(C) x^2/2
(D) x^2
(E) 3x^2/2

We can let the length = 2w and width = w. Using the Pythagorean theorem we have:

(2w)^2 + w^2 = x^2

4w^2 +w^2 = x^2

5w^2 = x^2

w√5 = x

w = x/√5, so the length is 2x/√5, and the area is 2x^2/5.

_________________

# Scott Woodbury-Stewart

Founder and CEO

Scott@TargetTestPrep.com
122 Reviews

5-star rated online GMAT quant
self study course

See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews

If you find one of my posts helpful, please take a moment to click on the "Kudos" button.

Re: A rectangle with diagonal length x is twice as long as it is wide. Wha   [#permalink] 24 Mar 2019, 18:43
Display posts from previous: Sort by