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A regular pentagon is inscribed in a circle. If A and B are

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Re: A regular pentagon is inscribed in a circle. If A and B are  [#permalink]

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New post 19 Sep 2014, 21:47
OK I ll come straight on the catch we have to find <OAB not <AOB ( Which is clearly 72 degree)
So 180-72 = 108/2=54(OAB angle)
Hope it helps :) Time taken :1.50 Secs
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A regular pentagon is inscribed in a circle. If A and B are  [#permalink]

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New post 27 Mar 2017, 10:57
bmwhype2 wrote:
A regular pentagon is inscribed in a circle. If A and B are adjacent vertices of the pentagon and O is the center of the circle, what is the value of ∠OAB ?

A. 48 degrees
B. 54 degrees
C. 72 degrees
D. 84 degrees
E. 108 degrees


∠0AB=(180-360/5)/2=54°
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Re: A regular pentagon is inscribed in a circle. If A and B are  [#permalink]

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Re: A regular pentagon is inscribed in a circle. If A and B are   [#permalink] 09 Feb 2020, 00:56

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