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655-705 Level|   Geometry|      
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navaljoshi
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A regular pentagon is inscribed in a circle. If A and B are 19 Sep 2014, 22:47
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OK I ll come straight on the catch we have to find <OAB not <AOB ( Which is clearly 72 degree)
So 180-72 = 108/2=54(OAB angle)
Hope it helps :) Time taken :1.50 Secs
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gracie
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A regular pentagon is inscribed in a circle. If A and B are 27 Mar 2017, 11:57
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bmwhype2
A regular pentagon is inscribed in a circle. If A and B are adjacent vertices of the pentagon and O is the center of the circle, what is the value of ∠OAB ?

A. 48 degrees
B. 54 degrees
C. 72 degrees
D. 84 degrees
E. 108 degrees

∠0AB=(180-360/5)/2=54°
B
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A regular pentagon is inscribed in a circle. If A and B are 05 Apr 2022, 12:20
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Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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