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27 Oct 2021, 01:30
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D
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Difficulty:
45%
(medium)
Question Stats:
66% (02:37) correct
34%
(02:00)
wrong
based on 38
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A right circular cylinder having the radius of its base as 2 centimeters is filled with water upto a height of 2 centimeters. This water is then poured into an empty rectangular container the dimensions of whose base are 2π by 3 centimeters. If the volume of water in the rectangular container is increased by 50 percent by adding extra water, what is the final height, in centimeters, of the water level in centimeters in the rectangular container?
A. 0.5
B. 1
C. 1.5
D. 2
E. 2.5
A. 0.5
B. 1
C. 1.5
D. 2
E. 2.5
asishron29181
Joined: 04 May 2020
Last visit: 04 Nov 2022
Posts: 185
Given Kudos: 68
Location: India
Schools: Great Lakes (I)
GMAT 1: 610 Q47 V27
WE:Programming (Computer Software)
27 Oct 2021, 08:14
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Volume of cylinder = π*(r)^2*h
=8π
Volume of rectangle = l*b*h
=6π*h
Volume of cylinder = volume of rectangular space (equal quantity of water)
8π = 6π*h
h = 4/3
More water is added and height increases by 50%.
New height = 1.5 * h = 1.5 * 4/3 = 2 cm
IMO D
=8π
Volume of rectangle = l*b*h
=6π*h
Volume of cylinder = volume of rectangular space (equal quantity of water)
8π = 6π*h
h = 4/3
More water is added and height increases by 50%.
New height = 1.5 * h = 1.5 * 4/3 = 2 cm
IMO D
27 Oct 2021, 19:42
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IMO: D
Volume of water = 2π(2)(2) = 2π(3)(h)
=> 8 = 6h
=> height occupied by water in rectangular container = 4/3
New height = 1.5*4/3 = 2
Volume of water = 2π(2)(2) = 2π(3)(h)
=> 8 = 6h
=> height occupied by water in rectangular container = 4/3
New height = 1.5*4/3 = 2
