Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 1811:00 AM PST
-12:00 PM PST
Join us in a live GMAT practice session and solve 30 challenging GMAT questions with other test takers in timed conditions, covering GMAT Quant, Data Sufficiency, Data Insights, Reading Comprehension, and Critical Reasoning questions.
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
Fish181
Joined: 13 Dec 2023
Last visit: 22 Jan 2025
Posts: 135
Given Kudos: 53
Status:Applying in R1 of 2024 to t15
Affiliations: University of Tennessee
Location: United States (CO)
Concentration: Strategy, Finance
GMAT Focus 1: 605 Q76 V84 DI80 
GMAT Focus 2: 615 Q78 V86 DI78
GPA: 3.62
WE:Analyst (Consumer Packaged Goods)
GMAT Focus 2: 615 Q78 V86 DI78
Posts: 135
Updated on: 18 Mar 2024, 12:49
Originally posted by Fish181 on 18 Mar 2024, 09:18.
Last edited by gmatophobia on 18 Mar 2024, 12:49, edited 1 time in total.
Last edited by gmatophobia on 18 Mar 2024, 12:49, edited 1 time in total.
formatted the question and corrected the tags
Kudos
Bookmarks
0.5 km: 3km
1.5 km: 9km
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
79% (02:29) correct
21%
(02:30)
wrong
based on 463
sessions
History
Date
Time
Result
Not Attempted Yet
A satellite is currently in a circular orbit with radius 32,714 km about the center of the earth.
Select for 0.5 km the increase, to the nearest whole kilometer, in the distance the satellite travels about the center of the earth during each revolution if the orbital radius of the satellite is increased by 0.5 km. And select for 1.5 km the increase, to the nearest whole kilometer, in the distance the satellite travels about the center of the earth during each revolution if the orbital radius of the satellite is increased by 1.5 km. Make only two selections, one in each column.
Select for 0.5 km the increase, to the nearest whole kilometer, in the distance the satellite travels about the center of the earth during each revolution if the orbital radius of the satellite is increased by 0.5 km. And select for 1.5 km the increase, to the nearest whole kilometer, in the distance the satellite travels about the center of the earth during each revolution if the orbital radius of the satellite is increased by 1.5 km. Make only two selections, one in each column.
| 0.5 km | 1.5 km | |
| 3km | ||
| 9km | ||
| 27km | ||
| 81km | ||
| 150km | ||
| 450km |
ShowHide Answer
Official Answer
0.5 km: 3km
1.5 km: 9km
29 Mar 2024, 01:01
Kudos
Bookmarks
A satellite is currently in a circular orbit with radius 32,714 km about the center of the earth.
Select for 0.5 km the increase, to the nearest whole kilometer, in the distance the satellite travels about the center of the earth during each revolution if the orbital radius of the satellite is increased by 0.5 km. And select for 1.5 km the increase, to the nearest whole kilometer, in the distance the satellite travels about the center of the earth during each revolution if the orbital radius of the satellite is increased by 1.5 km. Make only two selections, one in each column.
According to GMAC, Geometry does not appear on the Focus Edition, but questions, such as this one, on the official practice tests indicate that knowing some basic Geometry concepts that can be considered common knowledge is necessary for getting some Quant questions correct.
Among those concepts are the Pythagorean theorem and formulas for calculating the areas of basic shapes including rectangles, triangles, and circles.
Now, this question requires use of the formula for the circumference of a circle, which is \(C = 2πr = πd\). where \(C\) is the circumference, \(r\) is the radius, \(d\) is the diameter of the circle, and the value of \(π\) is approximately \(3.14\).
Given that formula, we can see that, any time we increase the radius of a circle, we increase the circumference of the circle by \(2π\) times the increase in the radius, or by about \(6.28\) times the increase in the radius.
So, to calculate the increase in the distance the satellite travels during each revolution, we can ignore the figure 32,714 and just multiply each increase in the radius by 6.28.
If the radius is increased by 0.5 km, the distance is increased by approximately 0.5 × 6.28 = 3.14, which rounded to the nearest whole kilometer is 3.
If the radius is increased by 1.5 km, the distance is increased by approximately 1.5 × 6.28 = 9.42, which rounded to the nearest whole kilometer is 9.
3km
9km
27km
81km
150km
450km
Correct answer: 3km, 9km
Select for 0.5 km the increase, to the nearest whole kilometer, in the distance the satellite travels about the center of the earth during each revolution if the orbital radius of the satellite is increased by 0.5 km. And select for 1.5 km the increase, to the nearest whole kilometer, in the distance the satellite travels about the center of the earth during each revolution if the orbital radius of the satellite is increased by 1.5 km. Make only two selections, one in each column.
According to GMAC, Geometry does not appear on the Focus Edition, but questions, such as this one, on the official practice tests indicate that knowing some basic Geometry concepts that can be considered common knowledge is necessary for getting some Quant questions correct.
Among those concepts are the Pythagorean theorem and formulas for calculating the areas of basic shapes including rectangles, triangles, and circles.
Now, this question requires use of the formula for the circumference of a circle, which is \(C = 2πr = πd\). where \(C\) is the circumference, \(r\) is the radius, \(d\) is the diameter of the circle, and the value of \(π\) is approximately \(3.14\).
Given that formula, we can see that, any time we increase the radius of a circle, we increase the circumference of the circle by \(2π\) times the increase in the radius, or by about \(6.28\) times the increase in the radius.
So, to calculate the increase in the distance the satellite travels during each revolution, we can ignore the figure 32,714 and just multiply each increase in the radius by 6.28.
If the radius is increased by 0.5 km, the distance is increased by approximately 0.5 × 6.28 = 3.14, which rounded to the nearest whole kilometer is 3.
If the radius is increased by 1.5 km, the distance is increased by approximately 1.5 × 6.28 = 9.42, which rounded to the nearest whole kilometer is 9.
3km
9km
27km
81km
150km
450km
Correct answer: 3km, 9km
General Discussion
18 Mar 2024, 11:55
Kudos
Bookmarks
The path distance can be represented by:
2pi(R+r)
where R is radius of Earth and r height of satellite above Earth.
R and pi don't change, so the the change in the length of its orbit is solely due to the change in r.
Therefore, with a change in r of 0.5 and 1.5, the path changes by:
2pi*.5 and 2pi*1.5, or:
~3 and ~9, respectively.
Posted from my mobile device
2pi(R+r)
where R is radius of Earth and r height of satellite above Earth.
R and pi don't change, so the the change in the length of its orbit is solely due to the change in r.
Therefore, with a change in r of 0.5 and 1.5, the path changes by:
2pi*.5 and 2pi*1.5, or:
~3 and ~9, respectively.
Posted from my mobile device
