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Here is the essential guide to securing scholarships as an MBA student! In this video, we explore the various types of scholarships available, including need-based and merit-based options.
01 Apr 2016, 08:09
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A school give scholarship of a total of $940,000 to students, the scholarship consist of 3 types $95,000, $35,000, and $10,000. What is the smallest possible number of students who take the scholarship?
A. 13
B. 14
C. 15
E. 16
E. 17
* A solution will be posted in two days.
A. 13
B. 14
C. 15
E. 16
E. 17
* A solution will be posted in two days.
01 Apr 2016, 08:41
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MathRevolution
A school give scholarship of a total of $940,000 to students, the scholarship consist of 3 types $95,000, $35,000, and $10,000. What is the smallest possible number of students who take the scholarship?
A. 13
B. 14
C. 15
E. 16
E. 17
* A solution will be posted in two days.
A. 13
B. 14
C. 15
E. 16
E. 17
* A solution will be posted in two days.
let the three be a,b,c..
so 95000a+35000b+10000c=940000..
lets simplify..
19a+7b+2c=188..
for min a+b+c, we have to have max number of bigger scholarship..
so lets substitute a as 9 , a as 10 goes more than 940..
19*9 + 7b+2c=188
7b+2c=188-171=17..
we have to have b as odd since 2c is even and SUM is ODD..
so b=1...
7*1+2c=17
or 2c=10..
c=5..
total a+b+c=9+1+5=15..
C
Ofcourse to be SURE we should check when a=8 too
Reason:- we have been forced to take FIVE 10000s instead of ONE 35000 and ONE 10000 as 5000 is left over..
04 Apr 2016, 00:58
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A school give scholarship of a total of $940,000 to students, the scholarship consist of 3 types $95,000, $35,000, and $10,000. What is the smallest possible number of students who take the scholarship?
A. 13
B. 14
C. 15
E. 16
E. 17
The number of first-place students=f
The number of second-place students=s
The number of third-place students=t
Then, an equation 95,000f+35,000s+10,000t=940,000 is derived.
In order for f+s+t to be minimum, f should be maximum followed by s and t.
Then, f=9, s=1, t=5 are derived and f+s+t=9+1+5=15.
Thus, C is the answer.
A. 13
B. 14
C. 15
E. 16
E. 17
The number of first-place students=f
The number of second-place students=s
The number of third-place students=t
Then, an equation 95,000f+35,000s+10,000t=940,000 is derived.
In order for f+s+t to be minimum, f should be maximum followed by s and t.
Then, f=9, s=1, t=5 are derived and f+s+t=9+1+5=15.
Thus, C is the answer.
