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12 Sep 2019, 21:39
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A semicircle has an area of \(40\pi\). What is its diameter?
(A) \(2√5\)
(B) \(2√10\)
(C) \(4√5\)
(D) \(4√10\)
(E) \(8√5\)
(A) \(2√5\)
(B) \(2√10\)
(C) \(4√5\)
(D) \(4√10\)
(E) \(8√5\)
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12 Sep 2019, 22:40
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The area of full Circle=40 pi Hence
r^2= 80
r=4√5
Answer is c
Posted from my mobile device
r^2= 80
r=4√5
Answer is c
Posted from my mobile device
Updated on: 13 Sep 2019, 08:52
Originally posted by Archit3110 on 13 Sep 2019, 02:50.
Last edited by Archit3110 on 13 Sep 2019, 08:52, edited 1 time in total.
Last edited by Archit3110 on 13 Sep 2019, 08:52, edited 1 time in total.
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Bunuel
A semicircle has an area of \(40\pi\). What is its diameter?
(A) \(2√5\)
(B) \(2√10\)
(C) \(4√5\)
(D) \(4√10\)
(E) \(8√5\)
(A) \(2√5\)
(B) \(2√10\)
(C) \(4√5\)
(D) \(4√10\)
(E) \(8√5\)
area -= pi * r^2/2 = 40 pi
solve for r= √80 ; 4√5 ; diameter ; 8√5
IMO E
